A store sells cheese in half a pound package a recipe calls fpr 1.72 pound of cheese how many packages does the chef need

Answer:

3.42

Step-by-step explanation:

24/7=3.42

Answer:

{6, 8, 10, 12, 14, 16, 18, 20, ...}

Step-by-step explanation:

even natural numbers >/= 6.

Thus this has no upper limit and the set is thus infinite.

The set of even natural numbers greater than or equal to 6 is

" The natural numbers are those numbers used for counting and ordering. Numbers used for counting are called cardinal numbers."

We know the natural numbers are:

{1, 2, 3, 4, 5, 6, 7,..........}

Now, the set of even natural numbers are:

{2, 4, 6, 8, 10...........}

Therefore, the set of even natural numbers greater than or equal to 6 is

{6, 8, 10, 12,..............}

Learn more about natural numbers here: https://brainly.com/question/8102087

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Answer:

D

Step-by-step explanation:

I hope thats correct

Answer:

3 eighths are needes to make up the rest of the measure.

Step-by-step explanation:

1/4 + 1/4 + 1/ 8 + x = 1

2/4 + 1/8+x=1

4/8 + 1/8+x=1

5/8 + x=1

x=1 - 5/8

x=3/8

We need three eights.(Because 3/8=1/8+1/8+1/8 and 1/8 represents an eights)

Answer:

2x+1=0.

2x=0-1.

2x=-1.

2x/2=-1/2.

x=-2.

3x+4=0

3x=0-4

3x=-4

3x/3=-4/3

[tex]x = 1 \frac{1 }{3} [/tex]

If [tex]k\in\mathbb{Z}[/tex] than [tex]k+1\in\mathbb{Z}[/tex] however any [tex]\mathbb{Z}[/tex] divided by 2 is in [tex]\mathbb{Q}[/tex].

But it is not so simple.

If [tex]k[/tex] is odd then [tex]k+1[/tex] is even but when even number is divided by 2, you get an odd number which is in [tex]\mathbb{Z}[/tex].

However if [tex]k[/tex] is even then [tex]k+1[/tex] is odd and when we divide that by 2, you get a number like for example [tex]\frac{5}{2}[/tex] which is not in [tex]\mathbb{Z}[/tex] but rather inside [tex]\mathbb{Q}[/tex]. There are fortunately no irrational numbers.

There is also a problem with zero, zero is neither odd nor even but still an integer. If your [tex]k[/tex] happens to be -1, [tex]k+1=0[/tex], and zero divided by 2 is still just 0 which is in [tex]\mathbb{Z}[/tex].

So to sum up,

If [tex]k[/tex] is odd and not -1, then [tex]\frac{k+1}{2}\in\mathbb{Z}[/tex].

Or to put it in math [tex]\forall k\in\mathrm{odd}-\{-1\}\cup\{0\}\implies\frac{k+1}{2}\in\mathbb{Z}[/tex].

If [tex]k[/tex] is even or -1, then [tex]\frac{k+1}{2}\in\mathbb{Q}[/tex].

Or to put it in math [tex]\forall k\in\mathrm{even}\cup \{-1\}\implies\frac{k+1}{2}\in\mathbb{Q}[/tex].

Notes:

[tex]\mathbb{Z}[/tex] is a set of integers.

[tex]\mathbb{Q}[/tex] is a set of rational numbers.

[tex]\mathbb{Z}\subset\mathbb{Q}[/tex] means integers are a subset of rational numbers, that is, every integer is a also a fraction, however not every fraction is an integer.

Hope this helps :)

Step-by-step explanation:

the correct aanswer is 3 is correct answermark me bbrainleast plz

Answer:

d is the answer

Step-by-step explanation:

mark me as brilliant

A glucose molecule is the smallest type of protein monomer of starch and cellulose largest of the carbohydrate polymers fundamental unit of genetic material.

A glucose molecule is the monomer of starch and cellulose.

Step-by-step explanation:

So from this, we can conclude that A glucose molecule is the monomer of starch and cellulose.

Learn more about glucose here:

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Answer:

1833 miles is the total distance if the model airplane.

9514 1404 393

Answer:

  (C)  g = f(-x)

Step-by-step explanation:

g is a reflection of f over the y-axis. Such a reflection replaces x with -x.

  g(x) = f(-x) . . . . . matches choice C

_____

Additional comment

(A) leaves the function unchanged.

(B) is a reflection over the x-axis

(C) is a reflection over the y-axis (applicable here)

(D) is a reflection over the origin (both x- and y-axes)

The guitar's volume was amplified, but it was hard to hear the notes since it was so loud.

What word or phrase is a signal word that a context clue might be nearby to help determine the meaning of "amplified"?

Step-by-step explanation:

Answer:

1/4

Step-by-step explanation:

Answer:

answer it's c)24...

Step-by-step explanation:

i think helping you..... please tell correct or no...

Step-by-step explanation:

Please mark me as brainlyest

Answer:

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

1+1×5−6+8×(4+4)−62 =

1+1x5-6+8x(8)-62 =

1+5-6+64-62 =

2

Hope this helps! :)

9514 1404 393

Answer:

  p = -3/4b -3/4

Step-by-step explanation:

Vectors are perpendicular when their dot product is zero.

  A·B = p(4) +b(3) -3(-1) = 4p +3b +3

We want this to be zero, so ...

  4p +3b +3 = 0

  4p = -3b -3

  p = -3/4b -3/4 . . . . the value of p that makes A⊥B

Answer:

No

Step-by-step explanation:

To write 97/1000 as a decimal you have to divide numerator by the denominator of the fraction.

We divide now 97 by 1000 what we write down as 97/1000 and we get 0.097

And finally we have:

97/1000 as a decimal equals 0.097

Answer:

[tex]{ \underline{ \sf{x \: is \: \: \{ \frac{ - 5 + i \sqrt{35} }{10} \} } \: \: and \: \: \{ \frac{ - 5 - i \sqrt{35} }{10} \}} }[/tex]

Step-by-step explanation:

[tex]5 {x}^{2} + 4x + 3 = 0 [/tex]

from quadratic formular:

[tex]{ \sf{x = \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a} }} [/tex]

general equation:

[tex] {ax}^{2} + bx + c = 0[/tex]

a is 5, b is 4 and c is 3:

substitute in formular:

[tex]{ \sf{x = \frac{ - 5± \sqrt{ {5}^{2} - (4 \times 5 \times 3) } }{(2 \times 5)} }} \\ \\ { \sf{x = \frac{ - 5± \sqrt{ - 35} }{10} }}[/tex]

but from complexes, i² = -1

[tex]{ \sf{x = \frac{ - 5± \sqrt{35 {i}^{2} } }{10} }} \\ \\ = { \sf{x = \frac{ - 5±i \sqrt{35} }{10} }}[/tex]

Here we want to see if the statement:

"A proper use of units can help us to determine the meaning of the slope of a linear function" is true or false.

We will see that it is true.

First, a general linear equation can be written as:

y = a*x + b

Where a is the slope, x is the independent variable, y is the dependent variable, and b is the y-intercept.

The proper use of units is:

y and b must have the same units.

x can have any type of units

The slope must have the quotient between the units of y and the units of x.

Where the proper use of units means that we have the same units on both sides of the expression.

Now, assume that we know the units of y and x.

For example:

y is miles  (then b is also in miles)

x is in hours

Then, with the proper use of units, we can see that the units of the slope are:

miles/hour, or miles per hour.

With this (only knowing the units of x and y) we can see that the slope will be a speed.

So yes, the proper use of units is really important, as this has a lot of information (particularly, the meaning of the slope in a linear equation)

Thus, the statement is true.

If you want to learn more, you can read:

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Answer:

4.  3,52  - Tenths                

   0.352 - Hundredths

5.  65.09 - Ones

   7.005 - Thousandths

6.  753.4 - Tens

    0.051 -  Hundredths

Step-by-step explanation:

all steps are in picture

Answer:

g(f(x))=x^2 + 14x + 48

Step-by-step explanation:

you insert (x+7) into every x in the g(x) equation, so g(x)=(x+7)^2 - 1. then you simplify it by doing (x+7)(x+7) which gets you x^2 + 14x + 49. then you subtract the 1 from the equation to get g(f(x))=x^2 + 14x + 48.

(g o f) (x) = g ( f(x) )

= (x+7)² – 1

= x² + 14x+49 – 1

= x² + 14x+48

If you want, (f o g ) (x) below is the solution ^_^

(f o g ) (x) = f ( g(x) )

= g(x) + 7

= x²-1 +7

= x² +6

I hope I helped you^_^

If these vectors are to be linearly independent, then there exists some not-all-zero choice for scalars [tex]c_1,c_2,c_3,c_4[/tex] such that

[tex]c_1(1,1,0,-1) + c_2(1,k,1,1) + c_3(5,1,k,1) + c_4(-1,1,1,k) = (0,0,0,0)[/tex]

We can recast this as a system of linear equations,

[tex]\begin{bmatrix}1&1&5&-1\\1&k&1&1\\0&1&k&1\\-1&1&1&k\end{bmatrix}\begin{bmatrix}c_1\\c_2\\c_3\\c_4\end{bmatrix} = \begin{bmatrix}0\\0\\0\\0\end{bmatrix}[/tex]

This system has a solution if the coefficient matrix on the left side is not singular. So we attempt to find k such that it *is* singular, i.e. the determinant is zero:

• A cofactor expansion along the first column gives

[tex]\begin{vmatrix}1&1&5&-1\\1&k&1&1\\0&1&k&1\\-1&1&1&k\end{vmatrix} = \begin{vmatrix}k&1&1\\1&k&1\\1&1&k\end{vmatrix} - \begin{vmatrix}1&5&-1\\1&k&1\\1&1&k\end{vmatrix} + \begin{vmatrix}1&5&-1\\k&1&1\\1&k&1\end{vmatrix}[/tex]

• Cofactor expansions along the first columns of the remaining 3x3 matrices give

[tex]\begin{vmatrix}k&1&1\\1&k&1\\1&1&k\end{vmatrix} = k \begin{vmatrix}k&1\\1&k\end{vmatrix} - \begin{vmatrix}1&1\\1&k\end{vmatrix} + \begin{vmatrix}1&1\\k&1\end{vmatrix} = k^3-3k+2[/tex]

[tex]\begin{vmatrix}1&5&-1\\1&k&1\\1&1&k\end{vmatrix} = \begin{vmatrix}k&1\\1&k\end{vmatrix} - \begin{vmatrix}5&-1\\1&k\end{vmatrix} + \begin{vmatrix}5&-1\\k&1\end{vmatrix} = k^2-4k+3[/tex]

[tex]\begin{vmatrix}1&5&-1\\k&1&1\\1&k&1\end{vmatrix} = \begin{vmatrix}1&1\\k&1\end{vmatrix} - \begin{vmatrix}5&-1\\k&1\end{vmatrix} + \begin{vmatrix}5&-1\\1&1\end{vmatrix} = -k^2 - 6k + 7[/tex]

It follows that

[tex]\begin{vmatrix}1&1&5&-1\\1&k&1&1\\0&1&k&1\\-1&1&1&k\end{vmatrix} = (k^3-3k+2) - (k^2-4k+3) + (-k^2 - 6k + 7) \\\\ \begin{vmatrix}\cdots\end{vmatrix} = k^3 - 2k^2 - 5k + 6 = (k-3)(k-1)(k+2)[/tex]

which makes the coefficient matrix singular if k = 3, k = 1, or k = -2.

Then the four vectors are linearly independent for

[tex]\left\{ k\in\mathbb R \mid k\not\in\{-2,1,3\}\right\}[/tex]

Answer:

243

Step-by-step explanation:

the answer is 243 for number 6

Answer:

all you gotta do is do 2430 divided by ten

Answer:

∠AOB + ∠BOC = ∠AOC we will be using this equation

x = 21   this is the value of x

Step-by-step explanation:

Angle AOC = 84

Angle AOB = 3x

Angle BOC = x

it is given that Angle AOC = 84so we just need to add Angle AOB and Angle BOC

now lets make the equation we that we will be using

∠AOB + ∠BOC = ∠AOC

3x + x = 84

4x = 84

x = 84 ÷ 4

x = 21

Step-by-step explanation:

Here, we have,

AOC=84°

AOB=3x

BOC=x

Now, the required equation will be;AOC=AOB+BOC[whole part axiom]

or, 84°=3x+x

or, 84°=4x

or, 84°÷4=x

or, x=21°

Thus, the equation to find the answer is AOC=AOB+BOC and the value of x is 21°.