Find the value of x for which ABCD must be a parallelogram.

Answer:

D. 40

Step-by-step explanation:

A central angle is equal to the measure of its corresponding arc.

angle AOB is a central angle and it's corresponding arc is arc AB

this means that arc AB = measure of angle AOB

If angle AOB = 80 degrees then arc AB equals 80 degrees too.

An inscribed angle is equal to half the measure of its intercepted arc.

Angle ACB is an inscribed angle and the arc it intercepts is arc AB

This means that angle ACB = 1/2 of arc AB

We have found that the measure of arc AB is 80 degrees.

This means that angle ACB = 1/2 of 80 which is 40

Answer:

-3/7

Step-by-step explanation:

It is asking to find the slope of the secant line going through points (2,f(2)) and (9,f(9)).

We must find f(2) by looking at the curve at x=2. We should see that y=2 there so f(2)=2.

We must find f(9) by looking at the curve at x=9. We should see that y=-1 there so f(9)=-1.

The slope of a line is calculated by finding the ratio of the change of y to the change of x.

(-1-2)/(9-2)

(-3)/(7)

-3/7

Step-by-step explanation:

it is shown in the above process.

hope you understand

Answer:

[tex]\displaystyle x_1 = 2-\sqrt{3} \text{ and } y_1 = \frac{\sqrt{3}-1}{2}[/tex]

Or:

[tex]\displaystyle x _ 2 = 2 + \sqrt{3} \text{ and } y _ 2 = -\frac{1+\sqrt{3}}{2}[/tex]

Step-by-step explanation:

We are given the equation:

[tex]\displaystyle (x^2 + 2xy) + i(y-1) = (x^2 -2x + 2y) - i(x +y)[/tex]

And we want to find the values of x and y such that the equation is true.

First, distribute:

[tex]\displaystyle (x^2 + 2xy) + i(y-1) = (x^2 -2x + 2y) +i(-x -y)[/tex]

If two complex numbers are equivalent, their real and imaginary parts are equivalent. Hence:

[tex]\displaystyle x^2 + 2xy = x^2 - 2x +2y \text{ and } y - 1 = -x -y[/tex]

Simplify:

[tex]\displaystyle 2xy = -2x +2y \text{ and }x = 1 - 2y[/tex]

Substitute:

[tex]\displaystyle 2(1-2y)y = -2(1-2y) + 2y[/tex]

Solve for y:

[tex]\displaystyle \begin{aligned} 2(y - 2y^2) &= (-2 + 4y) + 2y \\ 2y - 4y^2 &= 6y -2\\ 4y^2 + 4y - 2& = 0 \\ 2y^2 + 2y - 1 &= 0 \\ \end{aligned}[/tex]

From the quadratic formula:

[tex]\displaystyle \begin{aligned} y &= \frac{-(2)\pm\sqrt{(2)^2 - 4(2)(-1)}}{2(2)} \\ \\ &= \frac{-2\pm\sqrt{12}}{4} \\ \\ &= \frac{-2\pm2\sqrt{3}}{4}\\ \\ &= \frac{-1\pm\sqrt{3}}{2} \end{aligned}[/tex]

Hence:

[tex]\displaystyle y_1 = \frac{-1+\sqrt{3}}{2} \text{ or } y_2 = \frac{-1-\sqrt{3}}{2}[/tex]

Then:

[tex]\displaystyle x _ 1 = 1 - 2\left(\frac{-1+\sqrt{3}}{2}\right) = 1 + (1 - \sqrt{3}) = 2 - \sqrt{3}[/tex]

And:

[tex]\displaystyle x _ 2 = 1 - 2\left(\frac{-1-\sqrt{3}}{2}\right) = 1 + (1 + \sqrt{3}) = 2 + \sqrt{3}[/tex]

In conclusion, the values of x and y are:

[tex]\displaystyle x_1 = 2-\sqrt{3} \text{ and } y_1 = \frac{\sqrt{3}-1}{2}[/tex]

Or:

[tex]\displaystyle x _ 2 = 2 + \sqrt{3} \text{ and } y _ 2 = -\frac{1+\sqrt{3}}{2}[/tex]

indirect variation

Verification

[tex]\\ \rm\Rrightarrow s\propto \dfrac{1}{y}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{s_1}{t_2}=\dfrac{s_2}{t_1}[/tex]

[tex]\\ \rm\Rrightarrow s_1t_1=s_2t_2[/tex]

[tex] {x}^{2} - 17x - 60 \\ (x + 3)(x - 20)[/tex]

First we put parentheses and in each bracket we put (X) and then we put the signs x² is positive and the 17X before it is a negative q is positive with negative —> negative, and negative before 17X and negative before the 60 —> positive. And then the number that does not have (x) where did it come from, for example 60 came from 20 x 3 or 30 x 2...etc. We can verify this by multiplying the parentheses together and the same number comes out .

Or it can be checked by multiplying the first bracket 3 with x from the second parenthesis comes out 3X and negative 20 from the second parenthesis with X from the first parenthesis and subtract 3X from –20xcomes out –17X .

I hope I helped you^_^

Answer:

Yes the function is continuous f(5) = 13

Step-by-step explanation:

Replace the variable x with 5 in the expression

Simlify the results

f(5) = 3(5)-3

f(5) = 15=3

f(5) = 13

Plotting on a graph gives a coninous line with a positive gradient

y intercept (0,-2)

Please view the attached graph

Answer:

Area is 307.72 ft^2

Circumference is 43.96 ft

Step-by-step explanation:

Area is 2pir^2

Circumference is 2rpi

pi is about 3.14

A=2pi(7)^2

A= 98pi which is about 307.72 ft^2

C= 2(7)pi

C= 14pi which is about 43.96 ft

(I'm not sure whether they want the answer left in terms of pi or not)

Answer:

VW = 6

Step-by-step explanation:

To find x, set up the following equation:

(5x - 4) + (2x) = 5x

Solve out left side

7x - 4 = 5x

Subtract 5x from both sides

2x - 4 = 0

Add 4 to both sides

2x = 4

Divide both sides by 2

x = 2

Plug into 5x - 4

5(2) - 4

10 - 4

6

Answer:

6

Step-by-step explanation:

5x - 4 + 2x = 5x

7x - 4 = 5x

-4 = -2x

2 = x

5(2) - 4

10 - 4

6

Sorry I'm not sure if I'm right just my thinking...

set the number to be x so that (5x+2)(3x-4)??

Answer:

C. (Image 092618

Step-by-step explanation:

[tex]slope = \frac{y_{2} - y_{1} }{x _{2} - x_{1} } [/tex]

y1 is 2

y2 is -1

x1 is -3

x2 is 7

substitute:

[tex]slope = \frac{ - 1 - 2}{7 - ( - 3)} [/tex]

Answer:3

Step-by-step explanation:

-3x+2=-7

subtract 2 from both sides

-3x+2-2-(-7-2

simplify the arithmetic

-3x=-7-2

simplify the arithmetic aging

-3x=-9

=3

Answer:  [tex](x-9)^2 + (y-12)^2 = 225\\\\[/tex]

This is the same as writing (x-9)^2 + (x-12)^2 = 225

========================================================

Explanation:

Any circle equation fits the template of [tex](x-h)^2 + (y-k)^2 = r^2\\\\[/tex]

The center is (9,12) which tells us the values of h and k in that exact order.

h = 9

k = 12

To find the radius r, we need to find the distance from the center (9,12) to a point on the circle. The only point we know on the circle is the origin (0,0).

Apply the distance formula to find the distance from (9,12) to (0,0)

[tex]d = \sqrt{ (x_1-x_2)^2+(y_1-y_2)^2}\\\\d = \sqrt{ (9-0)^2+(12-0)^2}\\\\d = \sqrt{ (9)^2+(12)^2}\\\\d = \sqrt{ 81+144}\\\\d = \sqrt{ 225}\\\\d = 15\\\\[/tex]

The distance from (9,12) to (0,0) is 15 units. Therefore, r = 15

An alternative to finding this r value is to apply the pythagorean theorem. The distance formula is effectively a modified version of the pythagorean theorem.

---------------------

Since h = 9, k = 12 and r = 15, we can then say:

[tex](x-h)^2 + (y-k)^2 = r^2\\\\(x-9)^2 + (y-12)^2 = 15^2\\\\(x-9)^2 + (y-12)^2 = 225\\\\[/tex]

which is the equation of this circle.

My answer is in the picture

9514 1404 393

Answer:

  1 +i√3.5

Step-by-step explanation:

In vertex form, the equation is ...

  2(x² -2x +1) +7 = 0

  2(x -1)² +7 = 0

Then the solutions are ...

  (x -1)² = -7/2

  x = 1 ±i√3.5

One solution is 1+i√3.5.

Answer:

A

Step-by-step explanation:

For each point along it goes 1 point up, if it was 4x it'd go 4 points up

Answer:

-29

Step-by-step explanation:

(-14) + (-15) =

-14 - 15 =

-29

Answer:

3031081 / 40678884

Step-by-step explanation:

To solve this, we can find the surface area of the moon and Earth, and then see how much the moon covers the Earth. The surface area of a sphere is equal to 4πr², so the radius of the Earth is

4πr² = 4 * π * 6378²

and the radius of the moon is

4πr² = 4 * π * 1741²

To figure out how much of the Earth's surface that the moon covers, we can implement a ratio of moons:Earth. This will give us an understanding of how many moons go inside one Earth. We thus have

(4 * π * 1741²) : ( 4 * π * 6378²) = (4 * π * 1741²) / ( 4 * π * 6378²)

cross out the 4 * π in the numerator and denominator

1741²/6378²

Next, we want to make the denominator 1, as that gives us 1 Earth. To do this, we can divide both the numerator and denominator by 6378². Because we are applying the same expression to both the numerator and denominator, this is essentially multiplying the fraction by 1, keeping it the same. We thus have

(1741²/6378²)/(6378²/6378²)

≈0.0745/1

≈ 0.0745

To put this in a fraction, we would have

(1741²/6378²)/1

= (1741²/6378²)

= 3031081 / 40678884

Answer:

6 ft

Step-by-step explanation:

Answer:

7w+2=3w+94

Subtract 3w from both sides.

7w+2−3w=94

Combine 7w and −3w to get 4w.

4w+2=94

Subtract 2 from both sides.

4w=94−2

Subtract 2 from 94 to get 92.

4w=92

Divide both sides by 4.

w=492

Divide 92 by 4 to get 23.

w=23

Answer:

23

Step-by-step explanation:

7w + 2 = 3w + 94                      Subtract 2 from both sides

7w = 3w + 94 - 2

7w = 3w + 92                             Subtract 3w from both sides

4w = 92                                      Divide by 4

w = 92/4

w = 23

Answer:

the answer is in picture

Answer:

y = 68

A = 44

Step-by-step explanation:

No matter what may be true, that doesn't look like an a to me.

x = y = 68                x and y are opposite equal sides and are therefore =.

68 + 68 + A = 180  all triangles are 180 degrees.

136 + A = 180          Subtract 136 from both sides

A = 180 - 136

A = 44

Answer:

crisp, clean, formal, readable

Step-by-step explanation:

Answer:

Step-by-step explanation:

d

Answer:

2x + 2y - 4

Step-by-step explanation:

The opposite sides are congruent so perimeter (P) is

P = 2(x + 2) + 2(y - 4)

  = 2x + 4 + 2y - 8

  = 2x + 2y - 4

v=t^2-8t+15

[tex]\boxed{\sf {\displaystyle{\int}^b_a}x^ndx=\left[\dfrac{x^{n+1}}{n+1}\right]^b_a}[/tex]

[tex]\\ \sf\longmapsto s={\displaystyle{\int}}vdt[/tex]

[tex]\\ \sf\longmapsto s={\displaystyle{\int^4_2}}t^2-8t+15[/tex]

[tex]\\ \sf\longmapsto s=\left[\dfrac{t^3}{3}-8\dfrac{t^2}{2}+15t\right]^4_2[/tex]

[tex]\\ \sf\longmapsto s=\left[\dfrac{t^3}{3}-4t^2+15t\right]^4_2[/tex]

[tex]\\ \sf\longmapsto s=\left(\dfrac{4^3}{3}-4(4)^2+15(4)\right)-\left(\dfrac{2^3}{3}-4(2)^2+15(2)\right)[/tex]

[tex]\\ \sf\longmapsto s=\left(\dfrac{64}{3}-64+60\right)-\left(\dfrac{8}{3}-16+30\right)[/tex]

[tex]\\ \sf\longmapsto s=\left(\dfrac{64}{3}-4\right)-\left(\dfrac{8}{3}+14\right)[/tex]

[tex]\\ \sf\longmapsto s=\dfrac{64}{3}-4-\dfrac{8}{3}-14[/tex]

[tex]\\ \sf\longmapsto s=\dfrac{64}{3}-\dfrac{8}{3}-4-14[/tex]

[tex]\\ \sf\longmapsto s=\dfrac{46}{3}-18[/tex]

[tex]\\ \sf\longmapsto s=15.3-18[/tex]

[tex]\\ \sf\longmapsto s=|-2.7|[/tex]

[tex]\\ \sf\longmapsto s=2.7km[/tex]

Answer:

The product of any rational number and any irrational number will always be an irrational number.

Step-by-step explanation:

Answer:

can you submit the coordinet plane?

Step-by-step explanation:

Time taken:  2[tex]\frac{1}{3}[/tex] minutes = 7/3 minutes

Water released: 9[tex]\frac{4}{5}[/tex] gallons = 49/5 gallons

Rate of water flowing out:

Rate(in gallons/minute) = Water released (in gallons) / Time Taken (in minutes)

plugging the given values

Rate = [tex]\frac{\frac{49}{5} }{\frac{7}{3} }[/tex] = [tex]\frac{49}{5} * \frac{3}{7}[/tex]

Rate = 21/5 = 4.2 gallons/minute

Answer:

Time taken: 2\frac{1}{3}

3

1

minutes = 7/3 minutes

Water released: 9\frac{4}{5}

5

4

gallons = 49/5 gallons

Rate of water flowing out:

Rate(in gallons/minute) = Water released (in gallons) / Time Taken (in minutes)

plugging the given values

Rate = \frac{\frac{49}{5} }{\frac{7}{3} }

3

7

5

49

= \frac{49}{5} * \frac{3}{7}

5

49

∗

7

3

Rate = 21/5 = 4.2 gallons/minute

Step-by-step explanation:

i hope it helps

You're a square !!!1!!!!!!!!11