HELPPP!!!!!!
How far is weather station A from the storm?
44.6 miles
19.7 miles
42.2 miles
31.2 miles

Answers

Answer 1
Answer: Choice D)  31.2 miles

This value is approximate.

============================================================

Explanation:

Let's focus on the 48 degree angle. This angle combines with angle ABC to form a 90 degree angle. This means angle ABC is 90-48 = 42 degrees. Or in short we can say angle B = 42 when focusing on triangle ABC.

Now let's move to the 17 degree angle. Add on the 90 degree angle and we can see that angle CAB, aka angle A, is 17+90 = 107 degrees.

Based on those two interior angles, angle C must be...

A+B+C = 180

107+42+C = 180

149+C = 180

C = 180-149

C = 31

----------------

To sum things up so far, we have these known properties of triangle ABC

angle A = 107 degreesside c = side AB = 24 milesangle B = 42 degreesangle C = 31 degrees

Let's use the law of sines to find side b, which is opposite angle B. This will find the length of side AC (which is the distance from the storm to station A).

b/sin(B) = c/sin(C)

b/sin(42) = 24/sin(31)

b = sin(42)*24/sin(31)

b = 31.1804803080182 which is approximate

b = 31.2 miles is the distance from the storm to station A

Make sure your calculator is in degree mode.

Answer 2

The weather station A is 31.2 miles from the storm

From the triangle shown:

m<B = 90° - 48°

m<B = 42°

m<A = 17° + 90°

m<A = 107°

m<A + m<B + m<C = 180° (Sum of angles in a triangle)

107° + 42° + m<C = 180°

m<C = 180° - 149°

m<C = 31°

The distance between the weather stations A and B = 24 miles

That is, AB = 24 miles

The storm is at point C

The length AC is found by using the rule of sines:

[tex]\frac{sinC}{AB}=\frac{sinB}{AC} \\\\\frac{sin31}{24}=\frac{sin42}{AC} \\\\\frac{0.515}{24} = \frac{0.669}{AC} \\\\0.02146=\frac{0.669}{AC}\\\\AC=\frac{0.669}{0.02146} \\\\AC=31.2 miles[/tex]

The weather station A is 31.2 miles from the storm

Learn more on sine rule here: https://brainly.com/question/4372174


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a. Find the distance around the park to the nearest yard.
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[tex]X=190yd[/tex]

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[tex]\huge\text{Hey there!}[/tex]

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[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\huge\boxed{\frak{Amphitrite1040:)}}[/tex]

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