Is the product of a rational number and an irrational number always irrational?

Answer: Choice B

[tex]x^{1/8}y^{8}[/tex]

======================================================

Explanation:

The two rules we use are

[tex](a*b)^c = a^c*b^c[/tex]

[tex](a^b)^c = a^{b*c}[/tex]

When applying the first rule to the expression your teacher gave you, we can say that:

[tex]\left(x^{1/4}y^{16}\right)^{1/2} = \left(x^{1/4}\right)^{1/2}*\left(y^{16}\right)^{1/2}[/tex]

Then applying the second rule lets us say

[tex]\left(x^{1/4}\right)^{1/2}*\left(y^{16}\right)^{1/2} = x^{1/4*1/2}*y^{16*1/2} = x^{1/8}y^{8}[/tex]

Therefore,

[tex]\left(x^{1/4}y^{16}\right)^{1/2} = x^{1/8}y^{8}[/tex]

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In short, we just multiplied each exponent inside by the outer exponent 1/2.

So that explains why the exponents go from {1/4,16} to {1/8,8} for x and y in that exact order.

Answer:

Step-by-step explanation:

buzhou一=12212+13。8.12+13.8=25.8          25.8x9.4=?242.52242.522

The area of the trapezoid is given by A = 121.26 feet²

The Trapezoid is a 4 sided polygon. Two sides of the shape are parallel to each other and they are termed as the bases of the trapezoid. The non-parallel sides are known as the legs or lateral sides of a trapezoid.

There are three types of trapezoids , and those are given below:

a) Isosceles Trapezoid

b) Scalene Trapezoid

c) Right Trapezoid

The area of the Trapezoid is given by

Area of Trapezoid = ( ( a + b ) h ) / 2

where , a = shorter base of trapezium

b = longer base of trapezium

h = height of trapezium

Given data ,

Let the area of the trapezoid be represented as A

Now , the equation will be

Let the height of the trapezium be H = 9.4 feet

The shorter base of the trapezium a = 12 feet

The longer base of the trapezium b = 13.8 feet

Now , Area of Trapezoid = ( ( a + b ) h ) / 2

On simplifying the equation , we get

Area of Trapezium A = ( ( 13.8 + 12 ) 9.4 ) / 2

Area of Trapezium A = 121.26 feet²

Hence , the area of trapezium is 121.26 feet²

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Answer:

40%

Step-by-step explanation:

40+30+70=140

180-140= 40

Answer:

NL= 2 × HI

x+24 =2 × (X+16)

x+24=2x + 32

2x-x= 24-32

x= – 8

NL=x+24 = –8 +24= 16

So ; NL= 16

I hope I helped you^_^

Answer:

The decimal 0.6 is a rational number. It is the decimal form of the fraction 6/10.

Answer:

Yes. 0.6 is a rational number.

9514 1404 393

Answer:

  27 square units

Step-by-step explanation:

The height is measured perpendicular to the base, so it is convenient to use a base such that the height is easily found. Here, the vertical line is a suitable base, as the height is the horizontal distance from that to the opposite vertex.

  A = 1/2bh = 1/2(9)(6) = 27 . . . . square units = triangle area

The expression for the perimeter of the rectangle is 63.2x - 14.6.

Given that,

We Know that

Perimeter of the rectangle is

[tex]= 2(l+w)\\\\= 2 (7x + 3.1 + 24.6x - 10.4)\\\\= 2(31.6x - 7.3)[/tex]

= 63.2x - 14.6

Here the above formula should be applied for measuring the perimeter of the rectangle.

Therefore we can conclude that The expression for the perimeter of the rectangle is 63.2x - 14.6.

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Answer:

24.3

Step-by-step explanation:

First you solve the sides:

24.6-10.4 =14.2

7+3.1=10.1

After that ,you will add because perimeter is adding up the side lengths of various shapes.

14.2+10.1=24.3

Answer:

100.5

Step-by-step explanation:

As it's a straight line, the angles should add up to 180. So 8x+14+8x-7=180, 16x+7=180, x=10.8125, DEG will be 8x+14=100.5

Answer:

The union of two sets contains all the elements contained in either set (or both sets). The union is notated A ⋃ B. The intersection of two sets contains only the elements that are in both sets. The intersection is notated A ⋂ B.

Answer:

The union of a set A with a B is the set of elements that are in either set A or B. The union is denoted as A∪B. For example, if A is the set {♢,♡,♣,♠} and B is the set {△,♡,♠}, then A∪B={♢,♡,♣,♠,△}.

Intersection of two given sets is the largest set which contains all the elements that are common to both the sets. To find the intersection of two given sets A and B is a set which consists of all the elements which are common to both A and B. The symbol for denoting intersection of sets is '∩'.

Answer:

X-intercept: (-7, 0)

Y-intercept: (0, -14/4)

Step-by-step explanation:

To find the intercepts plugin 0 for one variable and solve

2x+3(0)=-14

x=-7

2(0)+3y=-14

y=-14/3

Answer:

15 cm.

Step-by-step explanation:

Recall that the arc-length of a circle is given by the formula:

[tex]\displaystyle s = r\theta[/tex]

Where r is the radius and θ is the measure of the central angle in radians.

The circle has a diameter of 24 cm, so its radius is 12 cm.

And its central angle is 1.25 radians. Hence, the arc-length will be:

[tex]\displaystyle s = \left(12\right)\left(1.25\right) = 15\text{ cm}[/tex]

In conclusion, the arc-length for a circle with a diameter of 24 cm subtended by a central angle of 1.25 radians is 15 cm.

[tex]2 {m}^{8} - 6 {m}^{2} [/tex]

Step-by-step explanation:

[tex](12 {m}^{7} - 36m) \div 6m[/tex]

➡️ [tex] \frac{1 {2m}^{7} - 36m }{6} \times m[/tex]

➡️ [tex] \frac{6(2 {m}^{7} - 6m)}{6} \times m[/tex]

➡️ [tex](2 {m}^{7} - 6m)m[/tex]

➡️ [tex]2 {m}^{8} - 6 {m}^{2} [/tex]

Answer:

Step-by-step explanation:

Answer: g(x) = (x+1)-3

Step-by-step explanation: Assuming you are moving from expression f to expression g, the plus one in the equation moves the vertex to the right one. subtracting three outside of the parenthesis moves the vertex down three, giving you a vertex of (1,-3). hope this helps!

Line 1-Line 2-Associative property .

Line 2-Line 3- Distributive property

Solution:-

[tex]\\ \rm\longmapsto (9+x)x[/tex]

[tex]\\ \rm\longmapsto x(x+9)[/tex]

[tex]\\ \rm\longmapsto x(9+x)[/tex]

[tex]\\ \rm\longmapsto x^2+9[/tex]

My answer is in the picture

[tex]6\cdot\square=9\\\\\square=9:6\\\\\square=\frac{9}{6}\rightarrow\square=\frac{3}{2} \ (\text{devide 9 and 6 by 3})[/tex]

Answer:

-18 is the right answer..

Answer:

2x + 3 + 3x +12 + 90 = 180 (degree )

5x +105=180 (degree )

5x= 180-105 (degree )

5x = 75 (degree )

x = 75/5 (degree )

x = 15 #

therefore, 2x + 3= 2*15 + 3

=30+3

= 33#

3x + 12 = 3*15+12

= 45 +12

= 57#

Answer:

you either need to score a perfect on one exam and get a 80 on the second or get two 90s on both exams.

Step-by-step explanation:

We need to find the equation which is equidistant to the given points.

[tex]A(-2,6,3)[/tex] and [tex]B(5,3,-3)[/tex]

This can be done using the distance formula.

Let us take a point [tex]P(x,y,z)[/tex] which is equidistant from both points so

[tex]\sqrt{(x+2)^2+(y-6)^2+(z-3)^2}=\sqrt{(x-5)^2+(y-3)^2+(z+3)^2}\\\Rightarrow y^2-12y+x^2+4x+z^2+49-6z=y^2-6y+x^2+z^2+6z+43-10x\\\Rightarrow 7x-3y-2z+1=0[/tex]

The required equation is [tex]7x-3y-2z+1=0[/tex]

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Answer:

x = 5

Step-by-step explanation:

x^2/(x + 5) = 25/(x+5)      Subtract the right side from both sides.

x^2/(x + 5) - 25/(x + 5) = 0

x^2 - 25

=======   = 0

x + 5

(x + 5)(x - 5)

============= = 0

(x + 5)

Cancel x + 5 in the numerator and denominator.

x - 5 = 0

x = + 5

Does it check?

x^2/(x + 5) = 25/(x + 5)

x = 5

5^2/(10) = 25/10

25/10 = 25/10 Yes it checks.

Given Data : Length = (7p - 10q) and Breadth = (2p - 9q)

Calculation :

⟹ Perimeter = 2(Length + Breadth)

⟹ Perimeter = 2(7p - 10q + 2p - 9q)

⟹ Perimeter = 2(9p - 19q)

⟹ Perimeter = 18p - 38q centimetres

The required perimeter of the rectangle is 18p - 38q centimeters.

It is required to find the required perimeter of the rectangle.

A rectangle is a type of quadrilateral, whose opposite sides are equal and parallel. It is a four-sided polygon that has four angles, equal to 90 degrees. A rectangle is a two-dimensional shape.

Given:

width of a rectangle = (2p - 9q) centimeters,

length measures= (7p - 10q) centimeters.

We know that

⟹ Perimeter = 2(Length + Breadth)

By put the value width and length in perimeter we get,

⟹ Perimeter = 2(7p - 10q + 2p - 9q)

⟹ Perimeter = 2(9p - 19q)

⟹ Perimeter = 18p - 38q centimeters

Therefore, the required perimeter of the rectangle is 18p - 38q centimeters.

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Answer:

-1

Step-by-step explanation:

f(-1) = 2|-1| + 3(-1)

|-1| = 1

=> f(-1) = 2(1) - 3

=> f(-1) = 2 - 3

=> f(-1) = -1

Step-by-step explanation:

[tex]w = x^4\sin(y^4z^3)[/tex]

The differential [tex]dw[/tex] is

[tex]dw = 4x^3\sin(y^4z^3)dx [/tex]

[tex]\:\:\:\:\:\:\:\:\:\:\:+ x^4\cos(y^4z^3)(4y^3z^3)dy [/tex]

[tex]\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:+ x^4\cos(y^4z^3)(3y^4z^2)dz[/tex]

I think the answer is A and C!

Answer:

B) Keeping A constant and decreasing B

C) Increasing A and keeping B constant

Step-by-step explanation:

I did it on Khan Academy :)

Answer:

98376

Step-by-step explanation:

Answer:

25d + 100

Step-by-step explanation:

I will call "d" the days passed

25d + 100