In an experiment, we can define 3 types of variables.
Independent variables: Are these ones that the scientist can control and modify, in this case, would be the kind of rubber for the tires.
Dependent variables: Are the variables that react to the changes in the independent variables. In this case, would be "how much lasts each type of rubber".
Controlled variables: Are all of these variables that also have an impact on the dependent variable, so we need to control them (fix them) so they do not affect the study of the independent variable.
So, for this particular experiment, to find controlled variables we need to think on what things do affect the durability of tires.
Some examples can be:
The material of the ground where the tires are being tested.The temperature of the ground where the tires are being tested.The type of car where the tires are being tested.The speed at which the tires are being tested.The internal pressure at which the tires are being tested.If you want to learn more, you can read:
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What is the density of water (in g/mL) to fouf significant figures at 6°C?
Answer :
0.9999432 g/cm^3
The density of water in g/ml up to 4 significant figures at 6°C is 0.9999432 g/cm³.
What are significant figures?Significant figures are used for establishment of a number which is presented in the form of digits. These digits give a meaningful representation to the numbers.
The significant figures are the significant digits which convey the meaning according to the accuracy. These provide precision to the numbers and hence are called as significant numbers.There are rules for counting significant figures which are as follows:
1)All non-zero digits are significant .
2)All zeroes which occur between non-zero digits are significant.
3)All zeroes to the left and right of a non-zero digit are not significant.
4) All zeroes on right of decimal are significant if a non-zero number follows them.
5)All zeroes on right side of non-zero digit are significant
Learn more about significant figures,here:
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Balancing oxidation-reduction reactions
Mg+ N2—>Mg3N2
Answer:
[tex]{ \sf{3Mg_{(s)} + N_{2(g)} →Mg _{3}N_{2(s)}}}[/tex]
Convert to standard notation.
9.3 x 10^-5
Answer:
9.3 x 10^ -5 in standard notation is 0.000093
Explanation:
Since 10 is raised to a -5, this means that there should be 5 zeros before the non-zero digits
