The difference between the compound interest and simple interest on a certain sum at 10% per annum for 2 years is ₹157. Find the sum​

Answer:

x = 3

Step-by-step explanation:

Given

[tex]2^{3x+1}[/tex] = [tex]2^{10}[/tex]

Since bases on both sides are equal, both 2, then equate the exponents

3x + 1 = 10 ( subtract 1 from both sides )

3x = 9 ( divide both sides by 3 )

x = 3

Answer:

Step-by-step explanation:

( C ). 112°

Answer: Approximately 18.33%

Work Shown:

11/60 = 0.1833 approximately

This decimal converts to 18.33% when moving the decimal point over to the right two spots. Round this value however you need to.

Answer:

There is no Image

So Instead

There should be the lowest extreme aka 0, and hights extreme (Whatever number is last) Then you've got average (The Middle) and n the middle of it is the median.

Answer:

-9x+20

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

in step 1, when expanding the bracket, ken needed to do 2×5y AS WELL as 2×-1 which they didn't do. the correct answer after the first step should be 10y-2=18

Step-by-step explanation:

1) -4

2) -8, -6, -4, -3, 0, 3, 5

3) (a) -8 + 5 - 3 - 2

-13 + 5

-8

(b) -7 - 9 + 4 + 3

-7 - 9 + 7

-9

It looks like the limit you want to compute is

[tex]\displaystyle L = \lim_{x\to0}\left(\frac x{\tan(x)}\right)^{\cot^2(x)}[/tex]

Rewrite the limand with an exponential and logarithm:

[tex]\left(\dfrac{x}{\tan(x)}\right)^{\cot^2(x)} = \exp\left(\cot^2(x) \ln\left(\dfrac{x}{\tan(x)}\right)\right) = \exp\left(\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)}\right)[/tex]

Now, since the exponential function is continuous at 0, we can write

[tex]\displaystyle L = \lim_{x\to0} \exp\left(\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)}\right) = \exp\left(\lim_{x\to0}\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)}\right)[/tex]

Let M denote the remaining limit.

We have [tex]\dfrac x{\tan(x)}\to1[/tex] as [tex]x\to0[/tex], so [tex]\ln\left(\dfrac x{\tan(x)}\right)\to0[/tex] and [tex]\tan^2(x)\to0[/tex]. Apply L'Hopital's rule:

[tex]\displaystyle M = \lim_{x\to0}\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)} \\\\ M = \lim_{x\to0}\dfrac{\dfrac{\tan(x)-x\sec^2(x)}{\tan^2(x)}\times\dfrac{\tan(x)}{x}}{2\tan(x)\sec^2(x)}[/tex]

Simplify and rewrite this in terms of sin and cos :

[tex]\displaystyle M = \lim_{x\to0} \dfrac{\dfrac{\tan(x)-x\sec^2(x)}{\tan^2(x)}\times\dfrac{\tan(x)}{x}}{2\tan(x)\sec^2(x)} \\\\ M= \lim_{x\to0}\dfrac{\sin(x)\cos^3(x) - x\cos^2(x)}{2x\sin^2(x)}[/tex]

As [tex]x\to0[/tex], we get another 0/0 indeterminate form. Apply L'Hopital's rule again:

[tex]\displaystyle M = \lim_{x\to0} \frac{\sin(x)\cos^3(x) - x\cos^2(x)}{2x\sin^2(x)} \\\\ M = \lim_{x\to0} \frac{\cos^4(x) - 3\sin^2(x)\cos^2(x) - \cos^2(x) + 2x\cos(x)\sin(x)}{2\sin^2(x)+4x\sin(x)\cos(x)}[/tex]

Recall the double angle identity for sin:

sin(2x) = 2 sin(x) cos(x)

Also, in the numerator we have

cos⁴(x) - cos²(x) = cos²(x) (cos²(x) - 1) = - cos²(x) sin²(x) = -1/4 sin²(2x)

So we can simplify M as

[tex]\displaystyle M = \lim_{x\to0} \frac{x\sin(2x) - \sin^2(2x)}{2\sin^2(x)+2x\sin(2x)}[/tex]

This again yields 0/0. Apply L'Hopital's rule again:

[tex]\displaystyle M = \lim_{x\to0} \frac{\sin(2x)+2x\cos(2x)-4\sin(2x)\cos(2x)}{2\sin(2x)+4x\cos(2x)+4\sin(x)\cos(x)} \\\\ M = \lim_{x\to0} \frac{\sin(2x) + 2x\cos(2x) - 2\sin(4x)}{4\sin(2x)+4x\cos(2x)}[/tex]

Once again, this gives 0/0. Apply L'Hopital's rule one last time:

[tex]\displaystyle M = \lim_{x\to0}\frac{2\cos(2x)+2\cos(2x)-4x\sin(2x)-8\cos(4x)}{8\cos(2x)+4\cos(2x)-8x\sin(2x)} \\\\ M = \lim_{x\to0} \frac{4\cos(2x)-4x\sin(2x)-8\cos(4x)}{12\cos(2x)-8x\sin(2x)}[/tex]

Now as [tex]x\to0[/tex], the terms containing x and sin(nx) all go to 0, and we're left with

[tex]M = \dfrac{4-8}{12} = -\dfrac13[/tex]

Then the original limit is

[tex]L = \exp(M) = e^{-1/3} = \boxed{\dfrac1{\sqrt[3]{e}}}[/tex]

Answer:

Perimeter = 38.8m

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

Answer:

39cm

Step-by-step explanation:

When you find the upper and lower bounds of values with decimals, you will decrease or increase the value by increments of 0.05. Since we are just trying to find the upper bound we will add 0.05 to the values we are given.

15.6 + 0.05 = 15.65cm

3.8 + 0.05 = 3.85cm

Now that we have those values, we can find the perimeter using the formula [ 2(L + W) ]

= 2(15.65 + 3.85)

= 2(19.5)

= 39cm

Best of Luck!

Answer:

g^-1(x)=x/2+3/2

Step-by-step explanation:

Answer: give me brainliest

Step-by-step explanation:

ax+by=a-b

ax=a-b-by

x=a-b-by/a←

bx-ay=a+b

substituting

b(a-b-by/a)-ay=a+b

ab-b²-b²y/a-ay=a+b

ab-b²-b²y-a²y/a=a+b

ab-b²-(b²+a²)y=a²+ab

-(b²+a²)y=a²+ab-ab+b²

(b²+a²)y=-(a²+b²)

y=-(a²+b²)/a²+b²

y=-1←

substituting value of y

x=a-b-b(-1)/a

x=a-b+b/a

x=a/a

x=1

Answer:

is 5

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

So first when dividing fractions you need to invert and multiply. Thus the fraction becomes:

1/4 * 20/1.

When simplified it becomes 20/4 which is 5.

HOPE THIS HELPED

Answer:

.75

Step-by-step explanation:

8 red marbles, 3 blue marbles, and 1 green marble = 12 marbles

P( not blue) = marbles that are not blue / total

                     =(8red+1 green) / 12

                     =9/12

                      = 3/4

                       .75

Answer:

15/22

Step-by-step explanation:

3/11 ÷ 2/5

3/11 x 5/2

3/11 x 5/2 = 15/22

3/11 divided by 2/5 is equal to 15/22.

Here, we have,

To divide fractions, we can multiply the first fraction by the reciprocal of the second fraction.

The reciprocal of a fraction is obtained by flipping the numerator and denominator.

Let's calculate 3/11 divided by 2/5:

(3/11) ÷ (2/5)

To divide, we multiply by the reciprocal:

(3/11) * (5/2)

Now, multiply the numerators together and the denominators together:

(3 * 5) / (11 * 2) = 15/22

Therefore, 3/11 divided by 2/5 is equal to 15/22.

To learn more on division click:

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Answer:

X=2

Step-by-step explanation:

8-x=6

there the answer is 2

Answer:

3

Step-by-step explanation:

This is a classic puzzle!  If you pick out three socks, and they have only 2 colors, you'll get at least one match because they can't be 3 different colors.

Answer:

Step-by-step explanation:

First off, your polynomial should be a third degree, not a second degree. That's probably why you didn't get someone to answer this for you already.

If x + 2k is a factor of that polynomial, then by the Zero Product Property

x + 2k = 0 and x = -2k. That means that, by the factor theorem, f(-2k) = 0 (which means that if you plug -2k in for all the x's you get a zero). Therefore,

[tex]3(-2k)^3+6k(-2k)^2-14(-2k)-3=0\\-24k+24k+28k-3=0\\28k-3=0\\28k=3\\k=\frac{3}{28}[/tex]

Answer:

the answer is in picture

Answer:

$680

Step-by-step explanation:

original price=$800

discount = 15%

discount in dollars= $800 *15%

discount=$120

cost=$800-$120

cost=$680

Answer:

104

Step-by-step explanation:

The measure of angle 4 for the given parallel lines and angle is equal to 26°.

In the figure the parallel lines and the transversal forms angle 1 , angle 2 , and angle 4.

As per the diagram,

Angle 1 is vertically opposite angle to angle 2.

This implies,

Measure of angle 1 = Measure of angle 2.

Here, Measure of angle 1 =  26 degrees.

⇒ Measure of angle 2 = 26 degrees ( vertically opposite angles)

Now , Angle 2 and angle 4 are corresponding angles.

⇒measure of angle 2 = measure of angle 4

⇒ Measure of angle 4 = 26 degrees.

Therefore, the measure of angle 4 is equal to 26°.

Learn more about measure here

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Answer:

The statement in the question is wrong. The series actually diverges.

Step-by-step explanation:

We compute

[tex]\lim_{n\to\infty}\frac{n^2}{(n+1)^2}=\lim_{n\to\infty}\left(\frac{n^2}{n^2+2n+1}\cdot\frac{1/n^2}{1/n^2}\right)=\lim_{n\to\infty}\frac1{1+2/n+1/n^2}=\frac1{1+0+0}=1\ne0[/tex]

Therefore, by the series divergence test, the series [tex]\sum_{n=1}^\infty\frac{n^2}{(n+1)^2}[/tex] diverges.

EDIT: To VectorFundament120, if [tex](x_n)_{n\in\mathbb N}[/tex] is a sequence, both [tex]\lim x_n[/tex] and [tex]\lim_{n\to\infty}x_n[/tex] are common notation for its limit. The former is not wrong but I have switched to the latter if that helps.

Answer:

[tex]\displaystyle \sum^{\infty}_{n = 1} \frac{n^2}{(n + 1)^2} = \text{div}[/tex]

General Formulas and Concepts:

Calculus

Limits

Series Convergence Tests

Step-by-step explanation:

*Note:

Always apply the nth Term Test as the first test to use for convergence.

Rules:

Step 1: Define

Identify

[tex]\displaystyle \sum^{\infty}_{n = 1} \frac{n^2}{(n + 1)^2}[/tex]

Step 2: Find Convergence

∴ by the nth Term Test, the series diverges.

Topic: AP Calculus BC (Calculus I + II)

Unit: Convergence Tests

Answer:

7

Step-by-step explanation:

no need to panic !

it is actually totally easy.

we have the complete, big angle at U (imagine you turn VU around U into UT) = 178 degrees.

VT is almost a straight line (then that angle would be 180 degrees). but only almost ...

anyway, the other 2 angles are just parts of the big angle, and we see that together they sum up to the big angle, as there is no other space for a part of the big angle left.

so

(14x - 11) + (12x + 7) = 178

14x - 11 + 12x + 7 = 178

26x - 4 = 178

26x = 182

x = 7

Find the percentage of the people who like Chocolate = chocolate/ total x 100

Percentage = 125/300 = 0.41666 x 100 = 41.6667 = 41.67 ( round as needed)

A full circle is 360 degrees.

The central angle = percentage of chocolate x 360:

0.416666 x 360 = 150

The central angle for chocolate is 150 degrees

9514 1404 393

Answer:

 B.  25 people

Step-by-step explanation:

The remainders tell you the number will be 1 more than some multiple of the least common multiple (LCM) of 2, 3, and 4. The LCM is 3·4 = 12, so we want some multiple (n) of that such that 12n+1 is a multiple of 5. We know this is the case for n=2.

The least number of people who could be in the club is 2·12+1 = 25.

Answer:

Your answer is K= 60

I hope it's helps you

Answer:

2°C

Step-by-step explanation:

outdoor temperature

Answer:

try photo math

Step-by-step explanation:

it may work for this problem