What is the final temperature of water given an initial temperature of 28 ˚C, a mass of 7 g, and heat (q) of 184 J (Specific Heat of water = 4.184 )?

Answers

Answer 1

Answer:34.28 Degree celcius

Explanation:The heat given is equal to the change in temperature multiplied by the mass and the specific heat capacity

This gives the equation:Q=mc∆T

Where Q=184,m=7, specific heat capacity=4.184,∆T=X-28,

But ∆T=Final temperature (T'')-Initial temperature (T')

Therefore the equation becomes

184=7×4.184(X-28)

Solving the remaining linear equation gives you X as 34.28°C


Related Questions

The mass of an atom of element x is equivalent to the total mass of 7 hydrogen atoms

Answers

hydrogen mass is 1, the atom with mass number 7 is Lithium

write any two effect of gravity​

Answers

The Earth's gravitational force accelerates objects when they fall. It constantly pulls, and the objects constantly speed up.

What are the differences of a physical change and a chemical change?

Answers

Answer:

a physical change only changes the look of something whereas a chemical change occurs when one thing has a reaction and it forms a new substance.

what happens when we mix stone in water observation ​

Answers

Answer:

hope it's help you dear

Explanation:

If one drops a stone into a pond, a very rapid, thin jet of water spouts upwards. ... A cavity forms behind the object during impact on the water surface. This cavity is subsequently compressed by hydrostatic pressure, which leads to the formation of the jet

Which of the following is an example of a change from gravitational potential
energy to kinetic energy?

Answers

Answer:

The speed of a roller coaster increases as gravity pulls it downhill and is greatest at its lowest point. Viewed in terms of energy, the roller-coaster-Earth system's gravitational potential energy is converted to kinetic energy

Explanation:

a ball held in the air is the example of a change from gravitational potential energy to kinetic energy.

what is the density of a 5 mL sample of 1.95g of Gold

Answers

Answer:

density=mass/volume

=1.95/5 = 0.39 g(mL)-¹

Assuming equimolar quantities of reactants, which compound will react to the greatest extent with boron trifluoride (BF3) in a Lewis acid-base reaction

Answers

BF3 is considered as lewis acid because it’s the acceptor of electron

NH3 is an example of a Lewis Base that will react extensively with BF3 to form the compound BF3NH3

To solve such this we must know the concept of acid-base reaction. Therefore, NH[tex]_3[/tex] is the compound that will react to the greatest extent with boron trifluoride (BF[tex]_3[/tex]) in a Lewis acid-base reaction.

What is chemical reaction?

Chemical reaction is a process in which two or more than two molecules collide in right orientation and energy to form a new chemical compound. The mass of the overall reaction should be conserved. There are so many types of chemical reaction reaction like combination reaction, double displacement reaction.

NH[tex]_3[/tex] is an example of a Lewis Base that will react extensively with BF[tex]_3[/tex] to form the compound NH[tex]_3[/tex] + BF[tex]_3[/tex] → [B (NH[tex]_3[/tex])F[tex]_3[/tex]].

Therefore, NH[tex]_3[/tex] is the compound that will react to the greatest extent with boron trifluoride (BF[tex]_3[/tex]) in a Lewis acid-base reaction.

Learn more about the chemical reactions, here:

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The reaction described by the equation X + Y Z
shown to have the following rate law:
R = K[X] [Y]
What is the effect on the rate if the concentration
of [X] is doubled and [Y] remains constant?

Answers

rate is doubled because Rate is proportional to the concentration of X

Is thallium, TI, a solid, liquid, or gas?

Answers

Answer:

Thallium is a Solid

Hope it helps

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You are unable to lift an object. Which property makes the object difficult to lift?(1 point)

mass

density

weight

volume

Answers

Answer:

You are unable to lift an object. Which property makes the object difficult to lift?(1 point)

weight

PLEASE HELP!!!!!!!!! WILL MARK BRAINLIEST

Answers

Answer:

19.278049929737628457607385688801

Explanation:

Volume = L * W * H

Volume = 17.78 * 9.21 * 4.45 = 728.70441

Density = Mass / Volume

Mass = 14,048

14,048 / 728.70441 = 19.278049929737628457607385688801

Density = 19.278049929737628457607385688801

Explanation:

So density = mass/volume

Using this formula we'll solve the question.

mass = 14,048g/1000 = 14.048 kg

volume = 17.78/100 x 9.21/100 x 4.45/100

volume = 0.3143 m³

density = 14.048 kg/ 0.3143 m³

density = 44.69 kg/m³

round off to = 44.7 kg/m³

Which of the following words means "the degree to which a measurement is precise and reliable"?

a. variable
b. accuracy
c. parameter
d. constant

Answers

B, because that’s the simplified definition of accuracy

h = 3.0 a + 28.2
A pediatrician uses the model above to estimate the height h of a girl, in inches, in terms of the girl's age a, in years. Based on the model, what is the estimated height of a 2-year-old girl?

Answers

Answer:

h = 34.2 in

Explanation:

h = 3.0a + 28.2

h = height of a girl.

a = age of a girl.

h = 3.0a + 28.2

h = 3.0(2) + 28.2

h = 6 + 28.2

h = 34.2

The estimated height of a 2-year-old girl is 34.2 in.

Hope this helps, thank you :) !!

Which of these outcomes is conclusive evidence that mixing sugar in water is a physical change?

Answers

Answer:

» Water changes from colorless to a pale colored solution.

» The solubility of water reduces because a saturated solution is formed.

» The freezing point of water decreases. [colligative property]

» The boiling point of water elevates [colligative property]

» The vapour pressure of water lowers [colligative property]

Explanation:

[tex].[/tex]

Phosphorous-32 has a half life of 14.3 days while radon-222 has a half-life of 3.8 days, so phosphorous-32 is considered more active.

a. True
b. False

Answers

The answer is B - False

Water is placed into a sealed jar and has a mass of 22.0 grams. The jar is placed in the freezer and the water turns to ice. The jar of ice is measured. The mass should be:

a. Slightly less than 22.0 grams
b. Exactly 22.0 grams
c. Slightly more than 22.0 grams

Answers

exactly 22.0 grams

because freezing is a physical change not a chemicl change..so nothing is taken away or added

ANSWER;

exactly 22.0 grams

because freezing is a physical change not a chemicl change..so nothing is taken away or added

List of choices for questions 20-24: A. (1) CH3MgBr, (2) H3O , (3) CH3MgBr, (4) H3O B. (1) LDA, (2) CH3I, (3) H3O C. (1) CH3MgBr, (2) H3O , (3) NaBH4, (4) H3O D. (1) DIBAH, (2) H3O E. (1) NaOH, heat, (2) SOCl2, (3) CH

Answers

Answer:

h30

Explanation:

compared to those
5. Electrons farther away from the nucleus in an atom have
closer to the nucleus.
O A. lower energy
OB. higher energy
O C. the same energy
O D. higher or lower energy, depending on the element

Answers

Explanation:

higher or lower energy, depending on the element

Answer:

B

Explanation:

The specific gravity of a vegetable oil is 0.92. What is the massgrams, of 330 mL of vegetable oil?

Answers

Answer:

HOPE THIS ANSWER WILL HELP YOU

What is 47.35 dL= mL?

Answers

Answer:

4.735 litres

Explanation:

10 dL = 1 litre

47.35 dL = 47.35/10 = 4.735 litres

When a liquid is at its boiling point, the vapor pressure of the liquid

Answers

When the liquid is at its boiling point the vapor pressure of the liquid increases

why hydrogen has dual nature?​

Answers

Answer:

Since hydrogen has a single electron in its valence shell, it exhibits dual nature. of the periodic table, or it can obtain one electron to complete its valency of two, such as halogens from Group 17. Since it only has one electron in its outer shell, hydrogen has a dual existence.

Explanation:

This means that, like a normal halogen, a hydrogen atom can easily gain an electron to form a complete outer shell, or lose an electron to form an alkali metal. Since it already has two electrons in its outer shell, hydrogen can be diatomic, rendering it unreactive.

Which of the following atoms is expected to have two unpaired electrons? 
Al
Mg
Na
None of the above​

Answers

Answer:

none of the above answers

In a year an adult cow produces around 3.571 x 10^27 molecules of methane CH4 a greenhouse gas how many moles of methane does this cow produce in a year

Answers

Answer:

[tex]\boxed{\boxed {\sf 5930.0 \ mol \ CH_4}}[/tex]

Explanation:

We are asked to find how many moles of methane (CH₄)  a cow produces in a year. We must convert molecules of methane to moles of methane. We will do this using Avogadro's Number or 6.022 × 10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance.

In this case, the particles are molecules of methane. There are 6.022 × 10²³ molecules of methane in 1 mole.

We will convert molecules to moles using dimensional analysis. Set up a ratio using Avogadro's Number.

[tex]\frac {6.022 \times 10^{23} \ molecules \ CH_4}{ 1 \ mol \ CH_4}[/tex]

We are converting 3.571 × 10²⁷ molecules of methane to moles, so we multiply the ratio by this value.

[tex]3.571 \times 10^ {27} \ molecules \ CH_4 *\frac {6.022 \times 10^{23} \ molecules \ CH_4}{ 1 \ mol \ CH_4}[/tex]

Flip the ratio. It is still the same value, but the units of molecules of methane cancel.

[tex]3.571 \times 10^ {27} \ molecules \ CH_4 *\frac { 1 \ mol \ CH_4}{6.022 \times 10^{23} \ molecules \ CH_4}[/tex]

[tex]3.571 \times 10^ {27} *\frac { 1 \ mol \ CH_4}{6.022 \times 10^{23} }[/tex]

[tex]\frac {3.571 \times 10^ {27}}{6.022 \times 10^{23} } \ mol \ CH_4[/tex]

[tex]5929.923613 \ mol \ CH_4[/tex]

The original measurement of molecules of methane( 3.571 × 10²⁷ molecules) has 4 significant figures, so our answer must have the same. For the number we calculated, that is the ones place. The 9 in the tenth place tells us to round the 9 in the ones place up to a 0, then the 2 in the tens place up to a 3.

[tex]5930 \ mol \ CH_4[/tex]

We must add a placeholder zero in the tenth place to reach 4 sig figs.

[tex]5930.0 \ mol \ CH_4[/tex]

The adult cow produces approximately 5930.0 moles of methane in a year.

b. Use the balanced equation to answer the following questions.
CuSO4(aq) + 2NaOH(aq) —->Cu(OH)2(s) + Na2SO4(aq)

i. What is the ratio of moles of CuSO4 to moles of NaOH?
ii. If 638.44 g CuSO4 reacts with 240.0 NaOH, which is the limiting reagent?
iii. Using the limiting reagent to determine how many grams of Cu(OH)2 should precipitate out in the reaction.
iv. If only 174.6g of Cu(OH)2 precipitate were actually collected from the reaction, what would the percent yield be?

Answers

Answer:

i. 1 : 2

ii. NaOH is the limiting reagent

iii. 292.5g

iv. 59.69%

Explanation:

I have the detailed and self-explanatory workings. will snap and post later. Battery percent at 15%, flashlight not working.

1. The ratio of CuSO₄ to NaOH is 1 : 2

2. The limiting reactant is NaOH.

3. The mass of Cu(OH)₂ that will precipitate out is 292.5 g.

4. The percentage yield of Cu(OH)₂ is 59.7%

1. Determination of the ratio of CuSO₄ to NaOH.

CuSO₄ + 2NaOH —> Cu(OH)₂ + Na₂SO₄

From the balanced equation above, we can see that the ratio of CuSO₄ to NaOH is 1 : 2

2. Determination of the limiting reactant.

CuSO₄ + 2NaOH —> Cu(OH)₂ + Na₂SO₄

Molar mass of CuSO₄ = 63.5 + 32 + (16×4) = 159.5 g/mol

Mass of CuSO₄ from the balanced equation = 1 × 159.5 = 159.5 g

Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol

Mass of NaOH from the balanced equation = 2 × 40 = 80 g

From the balanced equation above,

159.5 g of CuSO₄ reacted with 80 g of NaOH.

Therefore,

638.44 g of CuSO₄ will react with = (638.44 × 80) / 159.5 = 320.22 g of NaOH.

From the calculations made above, we can see that a higher mass (i.e 320.22 g) of NaOH than what was given (i.e 240 g) is needed to react completely with 638.44 g of CuSO₄.

Therefore, NaOH is the limiting reactant.

3. Determination of the mass of Cu(OH)₂ that will precipitate out.

CuSO₄ + 2NaOH —> Cu(OH)₂ + Na₂SO₄

Molar mass of Cu(OH)₂ = 63.5 + 2(16 + 1) = 97.5 g/mol

Mass of Cu(OH)₂ from the balanced equation = 1 × 97.5 = 97.5 g

From the balanced equation above,

80 g of NaOH reacted to produce 97.5 g of Cu(OH)₂.

Therefore,

240 g of NaOH will react to produce = (240 × 97.5) / 80 = 292.5 g of Cu(OH)₂

Thus, 292.5 g of Cu(OH)₂ precipitated out of the reaction.

4. Determination of the percentage yield.

Actual yield of Cu(OH)₂ = 174.6 gTheoretical yield of Cu(OH)₂ = 292.5 gPercentage yield of Cu(OH)₂ =?

Percentage yield = (Actual /Theoretical) × 100

Percentage yield of Cu(OH)₂ = (174.6 / 292.5) × 100

Percentage yield of Cu(OH)₂ = 59.7%

Learn more about percentage yield:

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calculate mass of MnO2 if 1 mole of KMnO4 completely burnt. 2KMnO4 -> K2MnO4+MnO2+O2​

Answers

Answer:  80 grams

Explanation:  

2KMnO4 -> K2MnO4+MnO2+O2​

2 moles of KMnO4 would produce 1 mole of MnO2, so 1 mole of KMnO4 would produce 0.5 moles of MnO4.  The molar mass of MnO4 is 160 g/mole.  1/2 mole of KMnO4 would therefore be (160 g/mole)*(0.5 moles) = 80 grams.

6. Heat from the sun reaches to us by
(a) radiation
(b) conduction
(c) convection
(d) all of these

PS. the one who gets it correct will be followed by me and also be marked as the brainliest!​

Answers

Answer:

radiation

....

.

.

.

.hi how r u

Is my answer correct

Answer:

Radiation

Explanation:

Heat from the sun reaches is by the process of radiation

when two atoms share four valence electrons the shared electrons form a/an ____

Answers

double bonds

2 electrons from each atoms

Illustrate the law of law of multiple proportions using the formation of SO2 and SO3 by sulphur and oxygen

Answers

As illustrated from law of multiple proportion, the mass of the oxygen which combined with a fixed mass of the sulphur is in simple whole number ratio of 2 is to 3 (2:3).

The law of Multiple proportion states that when two elements combine to form more than one compound, the mass of the second element, which combines with a fixed mass of the first element, will always be ratios of small whole numbers.

To illustrate the law of multiple proportion from sulphur and oxygen, we use the given compounds.

The reaction of oxygen with sulphur to form SO₂ and SO₃:

[tex]S \ + \ O_2 \ -----> SO_2\\\\2SO_2 \ + \ O_2 \ ---> \ 2SO_3[/tex]

atomic mass of oxygen = 16 g

atomic mass of sulphur = 32 g

In the formation of SO₂:

mass of sulphur = 32 g and mass of oxygen = (2x16) = 32 g

In the formation of SO₃:

mass of sulphur = 32 g and mass of oxygen = (3 x 16) = 48 g

Notice, while mass of sulphur is constant, mass of oxygen changed.

The ratio of mass of oxygen in the given two compounds = 32g : 48g = 2:3

Thus, based on the law of multiple proportion, the mass of the oxygen which combined with a fixed mass of the sulphur is in simple whole number ratio of 2 is to 3 (2:3).

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the internacional system of units is based on ?

Answers

Answer:

The international system of units is basic on 7 units.

Hope it helps you.
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