Which graph could represent a car that begins by increasing its speed, then travels at a constant speed, and then decreases its speed, as time increases?

A graph with time (minutes) on the horizontal axis and speed (miles per minute) on the vertical axis. Both axes are unnumbered. The speed begins at 0, goes up at first, is steady for a while, and then goes down over time.
A graph with time (minutes) on the horizontal axis and speed (miles per minute) on the vertical axis. Both axes are unnumbered. The speed begins in the middle of the vertical axis, goes down at first, is steady for a while, and then goes up over time.
A graph with time (minutes) on the horizontal axis and speed (miles per minute) on the vertical axis. Both axes are unnumbered. The speed begins at 0, goes up at first, goes down for a while, and then is steady over time.

Answer:

100

Step-by-step explanation:

Answer:

100 1- bedroom and 150 2- bedroom

Step-by-step explanation:

let x be the number of 1- bedroom apartments , then

x + 50 is the number of 2- bedroom apartments , so

x + x + 50 = 250 ( subtract 50 from both sides )

2x = 200 ( divide both sides by 2 )

x = 100

There are 100 1- bedroom apartments and 100 + 50 = 150 2- bedroom

Answer:

107 full and .103 of another

Step-by-step explanation:

6212/58 =

Answer:

-11,9.42,10,11.8

-11<9.42<10<11.8

Answer:

I think the answer is

-11, 9.24 ,10, 11.8

Area of rectangle = Length * Width

Area = 11.3 cm * 14.8 cm

Area = 167.24

Perimeter of rectangle = 2 (L + W)

Perimeter = 2 (11.3 cm + 14.8 cm)

Perimeter = 2 (26.1 cm)

Perimeter = 52.2 cm²

Area of rectangle is 167.24 cm²

Perimeter of rectangle is 52.2 cm²

Hi there!

The numbers you have written there are correct.

[tex]-5<x<0[/tex] is true for any value of x that is greater than -5 or less than 0.

When a number is less than 0, we know that it has to be negative.

However, it cannot be more negative than -5. It cannot be -5 either.

So, x could be -1, -2, -3, -4, -1/2, -2.3, -4.9, the list goes on.

I hope this helps!

Let the input be x

[tex]\\ \rm\Rrightarrow x\geqslant 70mg/dl[/tex]

[tex]\\ \rm\Rrightarrow x\leqslant 130mg/dl[/tex]

Now

[tex]\\ \rm\Rrightarrow 70mg/dl\leqslant x\leqslant 130mg/dl[/tex]

Or

[tex]\\ \rm\Rrightarrow 130mg/dl\geqslant x\geqslant 70mg/dl[/tex]

Answer:

70 ≤ x ≤ 130

130 ≥ x ≥ 70

Step-by-step explanation:

We know that a persons glucose level can only be equal to or between 70 and 130 mg/dL. We can create an inequality to represent this;

70 < x < 130

This means that anything in between will work but anything less or more will not. You can also write this inequality as 130 > x > 70.

In word form you would say this:

Best of Luck!

Answer:

24

Step-by-step explanation:

The scaled factor is 3 for all of them.

Answer:

2/52

Step-by-step explanation:

Answer:

It is 20 white marbles

step by step explanation:

Fraction of the yellow marbles:

[tex]1 - \frac{1}{4} - \frac{3}{8} = \frac{3}{8} [/tex]

let total number of marbles be x :

[tex]{ \sf{ \frac{3}{8} \: of \: x = 30 \: yellow \: marbles}} \\ \\ \frac{3}{8} \times x = 30 \\ \\ 3x = 30 \times 8 \\ 3x = 240 \\ x = 80[/tex]

Total marbles = 80 marbles

for white marbles:

[tex] = \frac{1}{4} \times 80 \\ \\ = 20[/tex]

Answer:

Step-by-step explanation:

Answer:

The value of 6 in 675,002 is 1,000 times greater than the value of 6 in 385,621.

Answer:

b. 9s^2 t^2

Step-by-step explanation:

If (x*y) ^ 2 = multiple of x and y then power 2

(x * y) ^2 is equal to (x^2 * y^2)

That makes 9s^2t^2

Answer:

Option B. 9s^2t^2 is the correct answer.

Step-by-step explanation:

I just completed it.

Step-by-step explanation:

Accounts balance=$20

Part time job salary=$110

Total balance

\begin{gathered}\\ \sf\longmapsto 110+20=130\$\end{gathered}

⟼110+20=130$

Now

Price of comics=$40

Price left for bike

\begin{gathered}\\ \sf\longmapsto 130-40=90\$\end{gathered}

⟼130−40=90$

After buying the dream bike, John's account balance will be -$110.

Let's calculate John's account balance after each transaction step by step:

1. Initial balance: $20

2. Weekly paycheck: +$110

  Account balance = $20 + $110 = $130

3. Buys comic books: -$40

  Account balance = $130 - $40 = $90

4. Buys dream bike: -$200

  Account balance = $90 - $200 = -$110

After buying the dream bike, John's account balance will be -$110. This means he will have a negative balance of $110, indicating that he owes the bank or whoever manages the account. It's important to be cautious with negative balances as they can result in overdraft fees or other penalties depending on the account type and the bank's policies.

To know more about account:

https://brainly.com/question/6975956

#SPJ3

Answer: 15:13

Step-by-step explanation: 7/7=3500

Answer:

the answer is 1 : 2.4 because for every 1 inch on the original image there are 2.4 inches on the modified image.

Step-by-step explanation:

Step 1:

Measure the change in X and Y of a single length of the original image.

X1 = 3.5

Y1 = 5

Step 2:

Measure the change in X and Y of the same length on the modified image.

X2 = 8.5

Y2 = 12.5

Step 3:

use formula SF = X2/X1 = Y2/Y1

(SF = Scale Factor Dilation)

(X2 and Y2 = change in X and Y of the same length on the modified image.)

(X1 and Y1 = change in X and Y of a single length of the original image.)

X2 = 8.5

8.5/X1

X1 = 3.5

8.5/3.5

8.5/3.5 = 2.4

2.4

1 : 2.4

Answer:

14

Step-by-step explanation:

Multiply 7 and 6, then 7 and -4: 42-28=?

Subtract: 42-28=14

Answer:

0.5 < x < 3

or (0.5, 3)

Step-by-step explanation:

-16t² + 56t + 2 = 26

Subtract both sides by 26

-16t² + 56t + 2 = 26

                 -26   -26

-16t² + 56t - 24 = 0

Divide both sides by -8 to simplify

(-16t² + 56t - 24)/8 = 0/8

2t² - 7t + 3 = 0

Factor

(x - 3)(2x - 1) = 0

Do this to find the x's

x - 3 = 0

 + 3  +3

x = 3

2x - 1 = 0

    + 1  + 1

2x = 1

2x/2 = 1/2

x = 0.5

0.5 < x < 3

This means the intervals will have to be between 0.5 and 3 seconds

Answer:

76.25

Step-by-step explanation:

Answer:

-1/4

Step-by-step explanation:

-0.25

Answer:

that's is my answer for the question

Answer:

you could have a 6 and then a -6

or a 3 and a -3

or 0 and 0

have 2 cards with the same number but one is negative

Step-by-step explanation:

Answer:

(22.5 , 1)

Step-by-step explanation:

Midpoint formula= [tex]\frac{x^1+x^{2} }{2} +\frac{y^{1} +2^{2} }{2} =Midpoint[/tex]

[tex]\frac{27+18}{2}[/tex]=22.5

3+-1=2

2/2=1

So, midpoint is (22.5 , 1)

You can also graph it out and use Pythagorean theorem but that would overcomplicate the problem.

Answer:

The choose D. y=|x|–1

Your choice is right

I hope I helped you^_^

Answer:

1) D: -8 < x ≤ 2, R: -4 ≤ y ≤ 11.

2) D: -8 ≤ x ≤ -3 U 2 ≤ x < ♾️,

R: -6 ≤ y ≤ -5 U -3 ≤ y < ♾️.

Differentiate both sides with respect to x and solve for the derivative dy/dx :

[tex]\dfrac{\mathrm d}{\mathrm dx}\left[x^2y^2+xy\right] = \dfrac{\mathrm d}{\mathrm dx}[2] \\\\ \dfrac{\mathrm d}{\mathrm dx}\left[x^2\right]y^2 + x^2\dfrac{\mathrm d}{\mathrm dx}\left[y^2\right] + \dfrac{\mathrm d}{\mathrm dx}\left[x\right]y + x\dfrac{\mathrm dy}{\mathrm dx} = 0 \\\\ 2xy^2 + x^2(2y)\dfrac{\mathrm dy}{\mathrm dx} + y + x\dfrac{\mathrm dy}{\mathrm dx} = 0 \\\\ (2x^2y+x)\dfrac{\mathrm dy}{\mathrm dx} = -2xy^2-y \\\\ \dfrac{\mathrm dy}{\mathrm dx} = -\dfrac{2xy^2+y}{2x^2y+x}[/tex]

This gives the slope of the tangent to the curve at the point (x, y).

If the slope of some tangent line is -1, then

[tex]-\dfrac{2xy^2+y}{2x^2y+x} = -1 \\\\ \dfrac{2xy^2+y}{2x^2y+x} = 1 \\\\ 2xy^2+y = 2x^2y+x \\\\ 2xy^2-2x^2y + y - x = 0 \\\\ 2xy(y-x)+y-x = 0 \\\\ (2xy+1)(y-x) = 0[/tex]

Then either

[tex]2xy+1 = 0\text{ or }y-x=0 \\\\ \implies y=-\dfrac1{2x} \text{ or }y=x[/tex]

In the first case, we'd have

[tex]x^2\left(-\dfrac1{2x}\right)^2+x\left(-\dfrac1{2x}\right) = \dfrac14-\dfrac12 = -\dfrac14\neq2[/tex]

so this case is junk.

In the second case,

[tex]x^2\times x^2+x\times x=x^4+x^2=2 \\\\ x^4+x^2-2 = (x^2-1)(x^2+2)=0[/tex]

which means either

[tex]x^2-1 = 0 \text{ or }x^2+2 = 0 \\\\ x^2 = 1 \text{ or }x^2 = - 2[/tex]

The second case here leads to non-real solutions, so we ignore it. The other case leads to [tex]x=\pm1[/tex].

Find the y-coordinates of the points with x = ±1 :

[tex]x=1 \implies y^2+y=2 \implies y=-2 \text{ or }y=1 \\\\ x=-1\implies y^2-y=2\implies y=-1\text{ or }y=2[/tex]

so the points of interest are (1, -2), (1, 1), (-1, -1), and (-1, 2).