You want to buy a $239,000 home. You plan to pay 20% as a down payment, and take out a 30 year loan for
the rest
a) How much is the loan amount going to be?
b) What will your monthly payments be if the interest rate is 5%?
$
c) What will your monthly payments be if the interest rate is 6%?
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Answer:

2,560

Step-by-step explanation:

necesitas sumar 4 veces 640 o multiplicar 4×640

9514 1404 393

Answer:

  P = 4z +5

Step-by-step explanation:

The side lengths are given as (z), (z+5), (2z). The perimeter is the sum of the side lengths:

  P = z +(z +5) +2z

  P = 4z +5

Using the normal probability distribution and the central limit theorem, it is found that there is a 0.04 = 4% probability that the mean ticket price exceeds $35.

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Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

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Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.  

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The average ticket price for a Spring Training baseball game is $32.61, with a standard deviation of $8.62.

This means that [tex]\mu = 32.61, \sigma = 8.62[/tex]

------------------------------------------

Sample of 40:

This means that [tex]n = 40, s = \frac{8.62}{\sqrt{40}}[/tex]

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In a random sample of 40 Spring Training tickets, find the probability that the mean ticket price exceeds $35.

This is 1 subtracted by the p-value of Z when X = 35, so:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{35 - 32.61}{\frac{8.62}{\sqrt{40}}}[/tex]

[tex]Z = 1.754[/tex]

[tex]Z = 1.754[/tex] has a p-value of 0.96.

1 - 0.96 = 0.04

0.04 = 4% probability that the mean ticket price exceeds $35.

A similar question is given at https://brainly.com/question/24342706

Step-by-step explanation:

Ans is 20 .

F union C whole complement is 20

Answer:

haha pues cuesta mas las hamburgesas porque toca ir al doctor despues

Step-by-step explanation:

Answer: A

Hello,

Step-by-step explanation:

center =(-3,1)

a=2

b=7

[tex]\dfrac{(x+3)^2}{4} +\dfrac{(y-1)^2}{49} =1\\\\or\\\\49*(x+3)^2+4(y-1)^2=14^2\\\\Answer\ A\\[/tex]

Answer:

C. $11.55

Step-by-step explanation:

First, multiply 4 by $0.85 to get an answer of $3.40. Next, multiply 6 by $1.25 to get an answer of $7.50. Add up the cost of the pencils and pens by adding $3.40 and $7.50 to get $10.90. Next, we have to add the tax. Multiply $10.90 by 0.06 to get $.65. Add the $.65 to the $10.90 for a grand total of $11.55. Hope this helps!

Answer:

Step-by-step explanation:

The answer is actually

Let:

S=1+2+3+4+5+6+7+8+9+n

We know the answer to the following infinite sum:

S2=1-1+1-1+1-1+1-1+1-1+1-1+1-....= - 1/2

We can therefore solve for this sum:

S3=1-2+3-4+5-6+7-8+9-....

We add them:

S3=      1-2+3-4+5-6+7-8...

S3=       +1-2+3-4+5-6+7-8...

        ________________

2S3=    1-1+1-1+1-1+1-1+1-....

Therefore:

2S3=S2=

Answer:

Step-by-step explanation:

The relation is x²+y²=r² with r being the radius

[tex]f(x)=y=\sqrt{r^2-x^2} \\\\domain(f(x))=[-r,r]\ or\ -r\leq x \leq r\\range(f(x))=[0,r]\ or\ 0\leq y \leq r\\\\\\\ g(x)=y=-\sqrt{r^2-x^2} \\domain(g(x))=[-r,r]\ or\ -r\leq x \leq r\\range(g(x))=[-r,0]\ or\ -r\leq y \leq 0\\\\[/tex]

Answer:

707.7, or 707

Step-by-step explanation:

0.18 x 7.85 g = 1.413 g/one bearing. Total amount of bearings: 1kg = 1000 g/1.413

Answer:

765

Step-by-step explanation:

1)4.25/100=0.0425

2)0.0425*3600=153

3)153*5=765

Answer:

The number is 5

BRAINLIEST, PLEASE!

Step-by-step explanation:

8x + 2 = 2(21)

8x + 2 = 42

8x = 40

x = 5

In the expression, the value of number is 5.

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

We can to given that;

The algebraic expression is,

''A number is multiplied by 8, and that product is added to 2. The sum is equal to the product of 2 and 21.''

Now,

Let a number = x

Hence, We can formulate;

⇒ x × 8 + 2 = 2 × 21

⇒ 8x + 2 = 42

Subtract 2 both side,

⇒ 8x + 2 - 2 = 42 - 2

⇒ 8x = 40

Divide by 8;

⇒ x = 5

Thus, The value of number = 5

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Answer:50.000+2000+400+80+9

Step-by-step explanation:

Answer:

50.000 + 2.000 + 400 + 80 + 9

Answer:

[tex] \frac{x + 11}{8} = - 3 \\ x + 11 = - 3 .8 \\ x = - 24 - 11 \\ x = - 33[/tex]

maaf jika salah

Answer:

x=-35

Step-by-step explanation:

x+11=-3*8

x+11=-24

x=-24-11

x=-35

a = 16

a1 = 1/6

n=9

an = a1 (r n-1)a9 = a1

a9 = 1/16 (-2 9-1)

a9 = 1/16 (-28)

a9 = 1/16 (256)

a9 = 16

I hope this helps :)

Answer:

(x-1.5)^2 -2.25

Step-by-step explanation:

divide 3 by 2 which is 1.5

(x-1.5)^2 -2.25

The two answers you are looking for are 16π m² and 50.24 m².

Solution:

Finding the area of the circle,

First, knowing what the area of a circle formula is:

A=πr²

Since knowing that the radius is half the length of the diameter,

If the diameter is 8, then the radius must be 4.

A=π(4)²

A=16π m²

Now, you have the first answer. If you want to express it differently,

Using 3.14 as pi,

So, therefore,

A=16(3.14)

A=50.24 m²

So, now, we can conclude that the two answers you are looking for for the area of this circle are 16π m² and/or 50.24 m².

Answer:

16pi and 50.24 m squared

Step-by-step explanation:

Answer:

Step-by-step explanation:

buzhou一=12212+13。8.12+13.8=25.8          25.8x9.4=?242.52242.522

The area of the trapezoid is given by A = 121.26 feet²

The Trapezoid is a 4 sided polygon. Two sides of the shape are parallel to each other and they are termed as the bases of the trapezoid. The non-parallel sides are known as the legs or lateral sides of a trapezoid.

There are three types of trapezoids , and those are given below:

a) Isosceles Trapezoid

b) Scalene Trapezoid

c) Right Trapezoid

The area of the Trapezoid is given by

Area of Trapezoid = ( ( a + b ) h ) / 2

where , a = shorter base of trapezium

b = longer base of trapezium

h = height of trapezium

Given data ,

Let the area of the trapezoid be represented as A

Now , the equation will be

Let the height of the trapezium be H = 9.4 feet

The shorter base of the trapezium a = 12 feet

The longer base of the trapezium b = 13.8 feet

Now , Area of Trapezoid = ( ( a + b ) h ) / 2

On simplifying the equation , we get

Area of Trapezium A = ( ( 13.8 + 12 ) 9.4 ) / 2

Area of Trapezium A = 121.26 feet²

Hence , the area of trapezium is 121.26 feet²

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Answer:

e) and f) doesn't exist.

Step-by-step explanation:

Other you can see in picture.

Answer:

9680 ft^2

Step-by-step explanation:

1 acre = 43,560 ft^2

(2/9) acre = (2/9)*43,560 ft^2

(2/9) acre = 9680 ft^2

The equation to represent the length of the snake in weeks:

[tex]L=2w+26[/tex]

Given:

A snake of lenght of 26 cemtimeters grows approximately 2 centimeter long each week.

To find:

The equation to represent the length of the snake in weeks

Solution:

Let the length of the snake in' w' weeks be 'L'.

The initial length of the snake on Carlo's birthday = 26 cm

At starting very first week the length of the snake was 26 cm. And after a week the lenght of the snake becomes 28 cm and then aftertwo weeks the length becomes 30 cm and so on.

Increase in length of the snake each week = 2 cm

And increase in length of the snake in 'w' weeks = (2×w) cm

And the length of the snake in terms weeks (w) will be given by equation:

[tex]L=2\times w+ 26\\L=2w+26[/tex]

The equation to represent the length of the snake in weeks:

[tex]L=2w+26[/tex]

Learn more about equation representation here:

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Answer:

If it goes to the left it becomes in the hundredths place meaning it decreases

Step-by-step explanation:

The profitability of the restaurant is when the function gives a value greater than 0. The franchise does not make a profit after 5, 3, 2 or 1 month of opening.

Given that:

[tex]P(t) = t^4 - 9t^3 + 24t^2 - 20t[/tex]

To calculate the profit, we simply substitute the values of t in the above equation.

(a) 5 months

This means [tex]t =5[/tex]

So, we have:

[tex]P(5) = 5^4 - 9\times 5^3 + 24 \times 5^2 - 20 \times 5[/tex]

[tex]P(5) = 0[/tex]

(b) 3 months

This means that [tex]t=3[/tex]

So, we have:

[tex]P(3) = 3^4 - 9 \times 3^3 + 24 \times 3^2 - 20 \times 3[/tex]

[tex]P(3) = -6[/tex]

(c) 2 months

This means that [tex]t = 2[/tex]

So, we have:

[tex]P(2) = 2^4 - 9 \times 2^3 + 24 \times 2^2 - 20 \times 2[/tex]

[tex]P(2) = 0[/tex]

(d) 1 month

This means that [tex]t = 1[/tex]

So, we have:

[tex]P(1) = 1^4 - 9 \times 1^3 + 24 \times 1^2 - 20 \times 1[/tex]

[tex]P(1) = -4[/tex]

For the restaurant to make a profit, the equation has to give a positive value. Since none of the values of t gives a positive value for P(t).

Then, we can say the franchise does not make a profit after 5, 3, 2 or 1 month of opening.

Read more about functions at:

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Answer:

This formula can also be written as \(y - {y}_{1} = m\left(x - {x}_{1}\right)\). The standard form of the straight line equation is \(y = mx + c\) where \(m\) is the gradient and \(c\) is the \(y\)-intercept.

Answer:

20000

Step-by-step explanation:

Answer:

X= –10

[tex] \frac{1}{2} x - 5 = - 10 \\ \frac{1}{2} x = - 10 + 5 \\ \frac{1}{2} x = - 5 \\ x = - 5 \times 2 \\ x = - 10[/tex]

I hope I helped you^_^

Answer:

x= –4/5 , x= 2

Step-by-step explanation:

5x²-6x-14=-6

5x² –6x –14 +6=0

5x²–6x –8=0

(5x+4)(x-2)=0

x=–4/5

x=2

Hi! I'm happy to help!

To solve this, we simply have to replace x with the given values.

First, we have -14, let's apply that:

(5·(-14²))-(6·(-14))-14=

Now, let's solve (using the order of operations):

(5·(-14²))-(6·(-14))-14=

(5·196)-(6·(-14))-14=

980-(6·(-14))-14=

980-(-84)-14=

980+84-14=

1064-14=

1050=

1050≠-6

Option 1 is incorrect.

Next, let's substitute 14 for x:

(5·14²)-(6·14)-14=

Now, let's solve:

(5·14²)-(6·14)-14=

(5·196)-(6·14)-14=

980-(6·14)-14=

980-84-14=

896-14=

880=

880≠-6

Option 2 is incorrect.

Now, let's substitute -7 for x:

(5·(-7²))-(6·(-7))-14=

Now, let's solve:

(5·(-7²))-(6·(-7))-14=

(5·49)-(6·(-7))-14=

245-(6·(-7))-14=

245-(-42)-14=

245+42-14=

287-14=

273=

273≠-6

Option 3 is incorrect.

Now, let's substitute 7 for x:

(5·7²)-(6·7)-14=

Now, let's solve:

(5·49)-(6·7)-14=

245-(6·7)-14=

245-42-14=

203-14=

189=

189≠-6

Option 4 is incorrect.

Now, let's substitute -2 for x, and solve:

(5·(-2²))-(6·(-2))-14=

(5·4)-(6·(-2))-14=

20-(6·(-2))-14=

20-(-12)-14=

20+12-14=

32-14=

18=

18≠-6

Option 5 is incorrect.

Now, let's substitute 2 for x and solve:

(5·2²)-(6·2)-14=

(5·4)-(6·2)-14=

20-(6·2)-14=

20-12-14=

8-14=

-6=

-6=-6

Option 6 is correct.

Now, let's substitute -1 for x and solve:

(5·(-1²))-(6·(-1))-14=

(5·1)-(6·(-1))-14=

5-(6·(-1))-14=

5-(-6)-14=

5+6-14=

11-14=

-3=

-3≠-6

Option 7 is incorrect.

Now, let's substitute 1 for x and solve:

(5·1²)-(6·1)-14=

5-(6·1)-14=

5-6-14=

-1-14=

-15=

-15≠-6

Option 8 is incorrect.

Now, let's substitute -4/5 for x and solve:

(5·(-4/5²))-(6·(-4/5))-14=

(5·0.64)-(6·(-4/5))-14=

3.2-(6·(-4/5))-14=

3.2-(-4.8)-14=

3.2+4.8-14=

8-14=

-6=

-6=-6

Option 9 is correct.

Now let's substitute 4/5 for x and solve:

(5·4/5²)-(6·4/5)-14=

(5·0.64)-(6·4/5)-14=

3.2-(6·4/5)-14=

3.2-4.8-14=

-1.6-14

-15.6

-15.6≠-6

Option 10 is incorrect.

To summarize, you should pick option 6, and option 9.

I hope this was helpful, keep learning! :D