Solve for x: |4x + 12| = 16 (5 points)

Group of answer choices

x = 7, x = −7

x = 1, x = −1

x = 1, x = −7

x = −1, x = 7

Answer:

its A

Step-by-step explanation:

i took the quiz :)

Answer:

B on edge 2022

Step-by-step explanation:

Answer:

The answer is no

Step-by-step explanation:

Is because if we divide 136 by 5 is gonna give us 27.2 and we don’t want the decimal. So we can’t divide 136 by 5. Another method is you can you at the last digit in this case is 6, six is not in the table of 5 so always the answer is going to be in decimal. 136[tex]:[/tex]5= 27.2

Step-by-step explanation:

x1=6

y1=8

x2=1

y2=6

then ,

distance =

[tex] \sqrt{(6 - 1) {?}^{2} { + (8 - 6)}^{2} } \\ \sqrt{25 + [/tex]

Answer:

6, because the slope is equivalent to the value of a / 4. you see the run is 4, double of two, so the answer that makes sense is 6 as it is double of three.

[tex]\\ \rm\Rrightarrow 2x(5-x)+3x^2[/tex]

[tex]\\ \rm\Rrightarrow 10x-2x^2+3x^2[/tex]

[tex]\\ \rm\Rrightarrow 10x+(-2+3)x^2[/tex]

[tex]\\ \rm\Rrightarrow 10x+x^2[/tex]

[tex]\\ \rm\Rrightarrow x^2+10[/tex]

Answer:

x = 47/7 or 6.714

Step-by-step explanation:

7 (x+3) = 72-4

7x + 21 = 68

7x = 68 - 21

7x = 47

x = 47/7 or 6.714

Answer:

-11

Step-by-step explanation:

-2+-9=

add like terms

-11

Answer:

Step-by-step explanation:

P=(2,-3)

Q=(a,a²-2a-3)

[tex]\Delta y=a^2-2a-3-(-3)=a^2-2a\\\Delta x=a-2\\\\\displaystyle \lim_{a \to 2} \dfrac{a^2-2a-3-(-3)}{a-2} \\\\=\lim_{a \to 2} \dfrac{a^2-2a}{a-2} \\\\=\lim_{a \to 2} \dfrac{a(a-2)}{a-2} \\\\=\lim_{a \to 2} \dfrac{a}{1} \\\\=\lim_{a \to 2} a \\\\=2\\[/tex]

Proof:

y'=(x²-2x-3)'=2x-2

y'(2)=2*2-2=2

Answer:

13, 14, 15

Step-by-step explanation:

13 + 14 + 15 = 42

Better explanation:

n + (n+1) + (n+2) = 42

42 - 2 - 1 = 39

n + n + n = 39

3n = 39  divide by 3 to isolate n

n = 13

So it starts with 13 and goes up from there.

Answer:

1)rs.6000

Step-by-step explanation:

1)30 000*20/100=rs.6000

Sorry I don't know the answers for other questions cause I don't know outright price

Answer:

$148

Step-by-step explanation:

$9.25 x 16 hours = $148

Step-by-step explanation:

[tex] \frac{2}{9} + \frac{1}{3} \\ by \: taking \: out \: the \: lcm \: of \: 9 \: and \: 3 \: \\ we \: get \: 9\: as \: lcm \\ now \\ \frac{2 \times 1 + 1 \times 3}{9} \\ \frac{2 + 3}{9} \\ \frac{5}{9} [/tex]

Answer:

less then 90º

Step-by-step explanation:

an acute angle is an angle which is less then 90º

Answer:

$14.50

Step-by-step explanation:

Is the answer because we don't put a decimmel pint after the number

The property of real numbers demonstrated in the given statement is the "Reflexive Property of Equality."

The Reflexive Property of Equality is one of the fundamental properties of real numbers, stating that any real number is always equal to itself. In mathematical terms, for any real number 'a,' the Reflexive Property is expressed as:

a = a

This property is self-evident, as it simply means that any quantity or value is identical to itself. In the provided statement, the cost of one item sold for $14.50 is precisely $14.50, showing that the item's cost is equal to itself.

To further illustrate this concept, consider any real number 'x.' According to the Reflexive Property, we have:

x = x

This applies to all real numbers, whether they are whole numbers, decimals, fractions, negative numbers, or irrational numbers. For example:

1 = 1

5.3 = 5.3

-2 = -2

π = π (pi)

No matter what value 'x' represents, the Reflexive Property holds true for all real numbers. It is a fundamental principle that underpins many mathematical operations and proofs.

In summary, the Reflexive Property of Equality states that any real number is equal to itself. The given statement, "The cost of one item sold for $14.50 is $14.50," exemplifies this property, showing that $14.50 is indeed equal to $14.50, thus reaffirming the reflexive nature of real numbers.

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Answer:n =21

Step-by-step explanation:

Therefore, In the similarity transformation of ΔACB to ΔEFD, ΔACB was dilated by a scale factor of 2, reflected across the y-axis, and moved through the translation 2 units

What is graph transformation?

The technique of altering an existing graph or graphed equation to create a different version of the following graph is known as graph transformation. In particular, the change of algebraic equations, it is a typical kind of algebraic problem.

Graphs can be extended, rotated, inverted, or any combination of these transformations; they can also be translated or moved along the xyxy plane. The formulas "move the function f(x)f(x) by cc units in some direction," "stretch the function f(x)f(x) by cc units," and "rotate the function f(x)f(x) by xx units about the xx-, yy-, or zz-axis" are frequently used in mathematical issues. In every instance, the transformation has specific, calculable effects on the underlying function.

Since the triangle ABC and DEF is similar

So we can write,

DE/BC=EF/AB=FD/CA

scale factor =Length of CA/length of DF

                     =6/3

                      =2:1

Reflected at y axis i.e x=0

and raised by 2 units.

Therefore, In the similarity transformation of ΔACB to ΔEFD, ΔACB was dilated by a scale factor of 2, reflected across the y-axis, and moved through the translation 2 units

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Step-by-step explanation:

for a=

[tex] \frac{s - n}{n} [/tex]

Answer:

[tex]\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}[/tex]

Answer:

The selling price of 21 articles is equal to the cost price of 18 articles. Find the loss percent. Answer: answer is 100/7 %

Answer:

ball$

Step-by-step explanation:

<3

Answer:

False.

Step-by-step explanation:

.

17+1= 18

12= -6

12-17= -5 + 1 =-4.

Answer:

False

Step-by-step explanation:

12- (17 + 1) = (12 - 17) + 1

PEMDAS says parentheses first

12- (18) = (-5) + 1

Then add and subtract

-6 = -4

They are not equal

Answer:

Step-by-step explanation:

[tex]U=\{(x,y)\ \zeta\ y=|x+1| \ and\ x \in \{-2,-1,0,1,2\}\ \}\\\\\begin{array}{|c|c|}x&y\\---&---\\-2&2\\-1&0\\0&2\\1 & 4\\2&6\\---&---\\\end{array}\\\\U=\{(-2,2),(-1,0),(0,2),(1,4),(2,6)\}\\[/tex]

Answer:

2 / (-2,2)

Step-by-step explanation:

Answer:

- 6[tex]x^{4}[/tex] + 14x³ + 8x² - 18x - 10

Step-by-step explanation:

Given

(3x² - 4x - 5)(- 2x² + 2x + 2)

Each term in the second factor is multiplied by each term in the first factor, that is

3x²(- 2x² + 2x + 2) - 4x(- 2x² + 2x + 2) - 5(- 2x² + 2x + 2) ← distribute parenthesis

= - 6[tex]x^{4}[/tex] + 6x³ + 6x² + 8x³ - 8x² - 8x + 10x² - 10x - 10 ← collect like terms

= - 6[tex]x^{4}[/tex] + 14x³ + 8x² - 18x - 10

Answer:

Step-by-step explanation:

Given,

[tex] \frac{ \sqrt[4]{9} \sqrt{9} }{ \sqrt[4]{ {9}^{5} } } [/tex]

[tex] = \frac{ \sqrt[4]{9} \sqrt{9} }{ \sqrt[4]{9 \times 9 \times 9 \times 9 \times 9} } [/tex]

[tex] = \frac{ \sqrt[4]{9} \sqrt{9} }{9 \sqrt[4]{9} } [/tex]

[tex] = \frac{ \sqrt{9} }{9} [/tex]

[tex] = \frac{ {9}^{ \frac{1}{2} } }{ {9}^{1} } [/tex]

[tex] = {9}^{ \frac{1}{2} - 1} [/tex]

[tex] = {9}^{ - \frac{1}{2} } (ans)[/tex]

Answer:

<ALS - <2 = <1

< LDA + <ADE = 180  degrees

Step-by-step explanation:

<ALS = <1+<2

<ALS - <2 = <1

< LDA + <ADE = 180  degrees since it forms a straight line

Answer:

97

Step-by-step explanation:

388 (number of tickets) / 4 (number of groups (adults, and the 3 times as many kids))

If the number of student tickets sold was three times the number of adult tickets sold, 97 adult tickets were sold.

Let's assume the number of adult tickets sold is 'x.'

According to the information given, the number of student tickets sold was three times the number of adult tickets sold. So, the number of student tickets sold is 3x.

The total number of tickets sold is the sum of the adult and student tickets, which is 388:

x + 3x = 388

Now, combine like terms:

4x = 388

To find the value of 'x,' divide both sides of the equation by 4:

x = 388 / 4

x = 97

To verify the result, let's find the number of student tickets:

Number of student tickets = 3 * 97 = 291

Now, let's add the adult and student tickets:

97 (adult) + 291 (student) = 388

The result checks out, and we have 97 adult tickets and 291 student tickets, which together sum up to the total of 388 tickets sold for the school play.

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