Answer:
B
Explanation:
The control is something that is meant to not be changed, the control is a comparison of the experimental.
what are the major parts of the ear?
Explanation:
1.The parts of the ear include:
External or outer ear, consisting of: Pinna or auricle. This is the outside part of the ear. ...
2.Tympanic membrane (eardrum). The tympanic membrane divides the external ear from the middle ear.
3.Middle ear (tympanic cavity) , consisting of: Ossicles. ...
4.Inner ear , consisting of: Cochlea.
Explanation:
The major parts of ear are:-
1) Outer ear
PinnaExternal auditory canalTympanic membrane2) Middle ear
MalleusIncusStapes3) Inner ear
CochleaSemicircular canalsVestibuleNo links please, links never work, this is science not physics
Which two claims about cats are most likely to be based on science?
A. Cats are the best animals to keep as pets.
B Whiskers help cats sense distances when hunting prey.
C. Cats spend more time sleeping than most other predators.
D. Seeing a black cat is likely to bring you bad luck.
Answer:
b and c are the answers
A is an opinion, D is a superstitious belief because they haven’t found Jesus obviously
a radioactive element has a half-life of 30 days. calculate the mass of the element that remains after 20 days if 100g of the element decays. Also, calculate the decay constant.
Explanation:
the answer is in the image above
Two trucks left the warehouse at the same time and drove in
the same direction along a straight road. One truck drove at 68
km/h while the other drove at 57 km/h. Find theirs distance
apart after2 hours.
10. Numerical problems:
b. A stone is thrown vertically upwards with an initial velocity of 20 m/sec.find the maximum height it reaches and the time taken by it to reach the height. (g = 10 m/s2).
c. A car is moving at a rate of 72 km/hr. How far does the car move when it stops after 4 seconds?
d. A bus starts from rest. If the acceleration is 2 m/s2, find
1. the distance travelled.
2. the velocity after 2 seconds.
e. A stone is thrown vertically upward with the velocity of 25 m/s. How longo it take to reach the maximum height? Also calculate the height.
with process please
Answer:
a)20 m,2s
Explanation:
Given
Initial velocity=20 m /sec
g=10 m/s square
v =0m/s
h =?
t =?
now,
v = U +gt
=v=20 +10t
Or,10t=20
Or,t=20
10
therfore ,2 s.
Again,
h=ut -1 gt square
2
Or, h=20×2-1×10(2)square (multiply and cut )2×5 =10
; 2
Or,40-5×4
therefore , 20m
11. What is the resolution of this ruler? 6-centimeters
six cm - centimeters
Worth 10 points! I will give brainliest!! Please help!!! See picture!
Answer:
The last option
Explanation:
maize is called monocot why?
Answer:
Rice, wheat, maize all have one cotyledon in their seed, so they are monocots. Explanation: The monocot plants have a single cotyledon. They have a fibrous root system, leaves in monocots have parallel venation.
Explanation:
Mass is measured in
a) Litters
b) Centimeter
c) Newton
d) Kilogram
Answer:
d) Kilogram.
Hope it helps youMass is measured in
a) Litters
b) Centimeter
c) Newton
d) Kilogram
A train is moving with the velocity of 10m/s . It attains an acceleration of 4m/s after 5 sec . find the distance covered by train at that time.
A box is 300 kg & it covers the area of 150 m2 find the pressure exerted by the box in the ground.
Answer:
If we assume that the box is a cube with 150 m² surface area
Area of 1 face = 150 m² / 6 = 25 m²
The box will exert a downward force of
Force = mass * acceleration due to gravity
Force = 300 kg * 9.81 m/s² N
Force = 2943 N
The box exerts a pressure ( force / unit area) = 2943 N / 25 m²
Pressure = 117.7 N/m²
Thank you, if you found this helpful please comment.
What's Centripetal force................
Answer:
a force that acts on a body moving in a circular path and is directed towards the centre around which the body is moving.
Answer:
A centripetal force is a force that makes a body follow a curved path. Its direction is always orthogonal to the motion of the body and towards the fixed point of the instantaneous center of curvature of the path.
what do you mean by acceleration of a body 10\s?
Answer:
it means that the body is moving with acceleration increased of 10m in every second.
If Bert the Bat travels eastward at 40 mph with a tailwind of 6 mph, what is his actual speed?
Answer:
36 mph.
Explanation:
Now Albert here is using the wind to his advantage but if say there was no wind then he would not have the 6 mph behind him so we subtract 6 from 40 to get 36. hope this helps :)
how many seconds are there in 1 day . solve along with steps
One minute has 60 seconds, One hour has 60 minutes and one day has 24 hours. Thus, 80 x 60 x 24 = 86,400 sec
if my answer helps you than mark me as brainliest
Answer:
[tex]thank \: you[/tex]
a) A car accelerates uniformly at 3.7 m s⁻² as it passes a stationary road train. The initial speed of the car is 30 m s⁻¹, and it reaches the speed limit of 130 km h⁻¹ as it passes the front of the cab. Calculate the length of the road train. Give your answer to 3 significant figures. include units in your answer.
b) The braking distance of a road train travelling at 15 m s⁻¹ is 70 m. Assuming that the same deceleration is applied at all speeds, calculate the braking distance of a road train travelling at 25 m s⁻¹
(a) The length of the train is 54.6 m
(b) The braking distance of the road train is 194.44 m
The given parameters:
acceleration of the car, a = 3.7 m/s²
initial velocity of the car, u = 30 m/s
final velocity of the car, v = 130 km/h = 36.11 m/s
To find:
the length of the trainThe length of the train is the distance travelled by the car
The distance traveled by the car is calculated as:
[tex]v^2 = u^2 + 2as\\\\2as = v^2 - u^2\\\\s = \frac{ v^2 - u^2}{2a} \\\\where;\\\\s \ is \ the \ distance \ travelled \ by \ the \ car\\\\s = \frac{(36.11)^2 - (30)^2}{2\times 3.7} \\\\s = 54.585 \ m\\\\s \approx 54.6 \ m[/tex]
Thus, the length of the train is 54.6 m
(b) The braking distance of a road train travelling at 25 m s⁻¹
[tex]a = \frac{v_1^2}{2s_1} = \frac{v_2^2}{2s_2} \\\\Given;\\\\s_1 = 70 \ m\\\\v_1 = 15 \ m/s\\\\v_2 = 25 \ m/s\\\\s_2 = ?\\\\2s_2v_1^2 = 2s_1v_2^2\\\\s_2 = \frac{ 2s_1v_2^2}{2v_1^2} \\\\s_2 = \frac{s_1v_2^2}{v_1^2} \\\\s_2 = \frac{70\times 25^2}{15^2} \\\\s_2 = 194.44 \ m[/tex]
Thus, the braking distance of the road train is 194.44 m
Learn more here: https://brainly.com/question/19572178
A shift inward of the production possibilities curve signifies that _
A. The demand for the products has increased, so the supply will increase
B. The available resources have increased, so potential production levels will increase
C. The available production resources have decreased, so potential production levels will decrease
D. The demand for the products has decreased so, the supply will decrease
Answer:
c
Explanation:
A shift inward of the production possibilities curve signifies that: C. The available production resources have decreased, so potential production levels will decrease.
A production possibilities curve (PPC) is also referred to as production possibilities frontier (PPF) and it can be defined as a curve that illustrates the maximum (best) combinations of two (2) products which can be produce in an economy if they both depend on these two (2) main factors;
Fixed technology. Fixed resources.Basically, the production possibilities curve (PPC) illustrates the maximum combinations of goods that are available with fixed technology and resources.
Furthermore, an inward shift of the production possibilities curve (PPC) signifies that the available resources used for production have decreased, so potential production levels would also decrease.
Read more: https://brainly.com/question/17053992
tides occurs in oceans but not in lakes.why?
Answer:
Explanation:
Tides occur in the ocean but nit in lakes because an ocean is a free flowing body of water that can travel a large area of the globe while a lake or pond only covers a small area of the earth so it is not affected by gravity as violently and in turn, prevents the formation of tides.
Can aurora be found in other planets?
Answer:
Yes
Explanation:
Any planet with a sufficiently dense atmosphere that lies in the path of the solar wind will have aurora. It has been discoveres in planets like Jupiter, Saturn, etc.
Answer:
yes
Explanation:
Burger Hut is trying to decide if it can receive money from the government for providing employees with insurance. Financial accounting or Management Accounting or Tax Accounting
We have that with these disciplines well defined, The Form of accounting that speaks the most Burger Huts situation is the discipline of Management Accounting
Firstly we define the Disciplines of Accounting below
Financial accounting
Financial Accounting, this is a branch of accounting that focuses mainly on the Recording,Encapsulating or Summing up and then Releasing a statement bearing the Affairs of a Business over a specific time frame.
Management Accounting
This Branch of accounting focuses on the use of existing Financial positions to make assessment of a business and determine the best way to move the business forward.
Tax Accounting
This is a branch of accounting that focuses on taxation.This branch is governed by stiff rule that ensure that business stay in check.
Therefore
With these disciplines well defined, The Form of accounting that speaks the most Burger Huts situation is the discipline of Management Accounting
For more information on this visit
https://brainly.com/question/19436415
seharitat -The distance of a panet from the earth is 2.5 x 10^7 km and the gravitational force between them them is 3.82 x 10^18 N. Mass of the planet and earth are equal, each being 5.98 x 10^24 Kg. Calculate the universal gravitation constant.
We know
[tex]\boxed{\sf F=G\dfrac{Mm}{r^2}}[/tex]
[tex]\\ \sf\longmapsto G=\dfrac{Fr^2}{Mm}[/tex]
[tex]\\ \sf\longmapsto G=\dfrac{3.82\times 10^{18}(2.5\times 10^7)^2}{(5.98\times 10^{24})^2}[/tex](M=m)
[tex]\\ \sf\longmapsto G=\dfrac{3.82\times 10^{18}(6.25\times 10^{14})}{35.7\times 10^{48}}[/tex]
[tex]\\ \sf\longmapsto G=\dfrac{23.87\times 10^{32}}{35.7\times 10^{48}}[/tex]
[tex]\\ \sf\longmapsto G=0.668\times10^{-16}[/tex]
[tex]\\ \sf\longmapsto G=6.68\times 10^{-15}[/tex]
can sound waves propagate in vacuum if yes why if no why not??
Answer:
please mark me brainliest
Explanation:
No, sound waves cannot travel in a vacuum. This is because sound waves are mechanical waves that need a medium (such as air and water) to travel. Sound in physics is defined as a vibration that propagates as an audible wave of pressure, through a medium such as a gas, liquid or solid.
14 km = m on conversions using a ladder method
eo *Write any two uses of good condutor of heat
any two uses of good conductor of heat are
aluminium, cooper, metal are good conductor of heat and they are used for making utensils.
gold, silver, are also good conductor of heat they are used for making jewelleries.
1 point
30. A ray passing through the centre of curvature of a concave mirror.
after reflection is reflected back along the same path. Which is the correct
figure for the above statement.
Explanation:
when the object is between the pole and focus
If a ball is rolling at a velocity of 1.5 m/s and has a momentum of 10.0 kg times m/s, what is the mass of the ball?
Answer:
Mass of the ball, M = 6.667 kg
Explanation:
Given data:
Momentum, Mo = 10.0 kgm/s
Velocity of the rolling ball, V = 1.5 m/s
Mass of the body, M = ?
Momentum, Mo = Mass, M x Velocity, V
10.0 kgm/s = M x 1.5 m/s
Divide each side by 1.5 m/s
M = 10.0 kgm/s / 1.5 m/s
M = (6⅔) kg
:. Mass of the ball, M = 6.667 kg
how do i solve this?
Answer:
hmmm i dont know....
Explanation:
i just wanted free point. TANKS YOU SIR!!
A wombat runs south in a straight line with an average velocity of 5 m/s for 4
minutes and then with an average velocity of 4 m/s for 3 minutes in the same
direction.
What is the wombats total displacement?
What is the average velocity during that time?
We have that
The wombats total displacement is
[tex]d_t=2100m[/tex]
The average velocity during that time is
[tex]v_{avg}=5m/s[/tex]
From the question we are told that:
initial Velocity [tex]V_1=5m/s[/tex]
initial Time [tex]T_1=4min=>240sec[/tex]
Final Velocity [tex]V_2=4m/s[/tex]
Final time [tex]T_2=3min=>180sec[/tex]
a)
Generally, the equation for displacement is mathematically given by
d_t=(Initial +final) displacement
Where
initial displacement
[tex]d_1=V_1*t_1\\\\d_1=5*240[/tex]
[tex]d_1=1200m[/tex]
Final displacement
[tex]d_2=V_2*t_2\\\\d_2=5*180[/tex]
[tex]d_2=900m[/tex]
Therefore
[tex]d_t=(Initial +final) displacement[/tex]
[tex]d_t=1200+900[/tex]
[tex]d_t=2100m[/tex]
b)
Generally, the equation for Average velocity is mathematically given by
[tex]v_{avg}=\frac{d_t}{t_1+t_2}[/tex]
[tex]v_{avg}=\frac{2100m}{240+180}[/tex]
[tex]v_{avg}=5m/s[/tex]
in conclusion
The wombats total displacement is
[tex]d_t=2100m[/tex]
The average velocity during that time is
[tex]v_{avg}=5m/s[/tex]
For more information on this visit
https://brainly.com/question/11934397
An ambulance is currently traveling at 15m/s, and is accelerating with a constant acceleration of 5 m/s^2. The ambulance is attempting to pass a car that is moving at a constant velocity of 30m/s. How far must the ambulance travel until it matches the car’s velocity?
Using 3rd equation of kinematics
[tex]\\ \rm\longmapsto v^2-u^2=2as[/tex]
[tex]\\ \rm\longmapsto s=\dfrac{v^2-u^2}{2a}[/tex]
[tex]\\ \rm\longmapsto s=\dfrac{30^2-15^2}{2(5)}[/tex]
[tex]\\ \rm\longmapsto s=\dfrac{900-225}{10}[/tex]
[tex]\\ \rm\longmapsto s=\dfrac{675}{10}[/tex]
[tex]\\ \rm\longmapsto s=67.5m[/tex]
Bob the American has just driven his car across the Canadian border when he sees a
speed limit sign of 85 kilometers/hour. His speedometer only shows his speed in
miles/hour. Convert the kilometers to miles so that Bob doesn't get a speeding ticket.
(Conversions: 1 mile = 5280 ft; 1 foot = 12 in.; 1 inch = 2.54 cm
Answer:
it equals 53 miles per hour
